How to implement Ajax request function in JS

This time I will show you how to implement Ajax request with JSFunction, what are the notes for JS to implement Ajax request function, the following is a practical case, let’s come together take a look.

Generally when we write web pages, if we use Ajax to request the server, we use JQuery and other encapsulated libraries to call it, which is relatively simple.

But generally these libraries have many functions and introduce too many things that we don't need. If we need to write a simple page with a single function, there is no need for such a huge library file. We can simply implement our own Ajax request function. The specific code is as follows:

var ajax = {};
ajax.x = function () {
 if (typeof XMLHttpRequest !== 'undefined') {
 return new XMLHttpRequest();
 }
 var versions = [
 "MSXML2.XmlHttp.6.0",
 "MSXML2.XmlHttp.5.0",
 "MSXML2.XmlHttp.4.0",
 "MSXML2.XmlHttp.3.0",
 "MSXML2.XmlHttp.2.0",
 "Microsoft.XmlHttp"
 ];
 var xhr;
 for (var i = 0; i < versions.length; i++) {
 try {
 xhr = new ActiveXObject(versions[i]);
 break;
 } catch (e) {
 }
 }
 return xhr;
};
ajax.send = function (url, method, data, success,fail,async) {
 if (async === undefined) {
 async = true;
 }
 var x = ajax.x();
 x.open(method, url, async);
 x.onreadystatechange = function () {
 if (x.readyState == 4) {
 var status = x.status;
 if (status >= 200 && status < 300) {
 success && success(x.responseText,x.responseXML)
 } else {
 fail && fail(status);
 }
 }
 };
 if (method == 'POST') {
 x.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
 }
 x.send(data)
};
ajax.get = function (url, data, callback, fail, async) {
 var query = [];
 for (var key in data) {
 query.push(encodeURIComponent(key) + '=' + encodeURIComponent(data[key]));
 }
 ajax.send(url + (query.length ? '?' + query.join('&') : ''), 'GET', null, callback, fail, async)
};
ajax.post = function (url, data, callback, fail, async) {
 var query = [];
 for (var key in data) {
 query.push(encodeURIComponent(key) + '=' + encodeURIComponent(data[key]));
 }
 ajax.send(url,'POST', query.join('&'), callback, fail, async)
};

Usage: GET

ajax.get('/test.php', {foo: 'bar'}, function(response,xml) {
 //success
},
function(status){
 //fail
});
POST
ajax.post('/test.php', {foo: 'bar'}, function(response,xml) {
 //succcess
},function(status){
 //fail
});

There is a problem that needs to be noted here. If we want to send something like

var sendCmd = "?op_code=" + code + "&op_cmd=" + cmd;
ajax.post('/control' + sendCmd,'',function(response,xml) {
 console.log('success');
},
function(status){
 console.log('failed:' + status);
});

, I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!

Recommended reading:

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The above is the detailed content of How to implement Ajax request function in JS. For more information, please follow other related articles on the PHP Chinese website!