Example of uniform assignment of array elements in numpy

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The overall array processing and assignment operation in Numpy has always made me a little confused, and many times I don’t understand it deeply. Today I will list the relevant knowledge points separately and summarize them.

Let’s look at two small examples of code snippets:

Example 1:

In [2]: arr =np.empty((8,4))
 
In [3]: arr
Out[3]:
array([[ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.]])
 
In [4]: arr[1] = 1
 
In [5]: arr
Out[5]:
array([[ 0., 0., 0., 0.],
    [ 1., 1., 1., 1.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.],
    [ 0., 0., 0., 0.]])

Example 2:

In [6]: arr1 =np.empty(2)
In [8]: arr1
Out[8]:array([ 7.74860419e-304,  7.74860419e-304])
 
In [9]: arr1 = 0
 
In [10]: arr1
Out[10]: 0

These two paragraphs seem to have inconsistent behavior. In fact, it can still be understood using the general object-oriented label understanding model.

In Example 1, the label after adding the index actually refers to the specific storage area, while in Example 2, a label is used directly. So how to implement the overall assignment of a one-dimensional array? In fact, you only need to index all elements.

The specific method is as follows:

In [11]: arr1 =np.empty(2)
 
In [12]: arr1
Out[12]: array([0., 0.])
 
In [13]: arr1[:]
Out[13]: array([0., 0.])
 
In [14]: arr1[:] =0
 
In [15]: arr1
Out[15]: array([0., 0.])

It seems like It's quite simple, but without some in-depth analysis, it is indeed a little difficult to understand.

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