


Methods to convert matrices into lists and other functions in Python's numpy library_python
Below I will share with you a method for converting matrices into lists and other functions in Python's numpy library. It has a good reference value and I hope it will be helpful to everyone. Let’s take a look together
This article mainly introduces some functions in Python’s numpy library and makes a backup for easy search.
(1) Function to convert matrix to list: numpy.matrix.tolist()
Return list list
Examples
>>>
>>> x = np.matrix(np.arange(12).reshape((3,4))); x matrix([[ 0, 1, 2, 3], [ 4, 5, 6, 7], [ 8, 9, 10, 11]]) >>> x.tolist() [[0, 1, 2, 3], [4, 5, 6, 7], [8, 9, 10, 11]]
(2) Convert the array Function to convert to list: numpy.ndarray.tolist()
#Notes: (The array can be reconstructed)
The array may be recreated, a=np. array(a.tolist()).
Examples
>>>
>>> a = np.array([1, 2]) >>> a.tolist() [1, 2] >>> a = np.array([[1, 2], [3, 4]]) >>> list(a) [array([1, 2]), array([3, 4])] >>> a.tolist() [[1, 2], [3, 4]]
(3) numpy.mean() calculates the mean of a matrix or array:
Examples
> ;>>
>>> a = np.array([[1, 2], [3, 4]]) #对所有元素求均值 >>> np.mean(a) 2.5 >>> np.mean(a, axis=0) #对每一列求均值 array([ 2., 3.]) >>> np.mean(a, axis=1) #对每一行求均值 array([ 1.5, 3.5])
(4) numpy.std() calculates the standard deviation of a matrix or array:
Examples
##>>>>>> a = np.array([[1, 2], [3, 4]]) #对所有元素求标准差 >>> np.std(a) 1.1180339887498949 >>> np.std(a, axis=0) #对每一列求标准差 array([ 1., 1.]) >>> np.std(a, axis=1) #对每一行求标准差 array([ 0.5, 0.5])
(5) numpy.newaxis adds a dimension to the array:
Examples:
>>> a=np.array([[1,2,3],[4,5,6],[7,8,9]]) #先输入3行2列的数组a >>> b=a[:,:2] >>> b.shape #当数组的行与列都大于1时,不需增加维度 (3, 2) >>> c=a[:,2] >>> c.shape #可以看到,当数组只有一列时,缺少列的维度 (3,) >>> c array([3, 6, 9])
>>> d=a[:,2,np.newaxis] #np.newaxis实现增加列的维度 >>> d array([[3], [6], [9]]) >>> d.shape #d的维度成了3行1列(3,1) (3, 1) >>> e=a[:,2,None] #None与np.newaxis实现相同的功能 >>> e array([[3], [6], [9]]) >>> e.shape (3, 1)
(6) numpy.random.shuffle(index): Disrupt the order of the data set (array):
Examples:
>>> index = [i for i in range(10)] >>> index [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] >>> np.random.shuffle(index) >>> index [7, 9, 3, 0, 4, 1, 5, 2, 8, 6]
(7) Calculate a certain row or a certain number of two-dimensional array Maximum and minimum value of a column:
>>> import numpy as np >>> a = np.arange(15).reshape(5,3) #构造一个5行3列的二维数组 >>> a array([[ 0, 1, 2], [ 3, 4, 5], [ 6, 7, 8], [ 9, 10, 11], [12, 13, 14]]) >>> b = a[:,0].min() ##取第0列的最小值,其他列同理 >>> b 0 >>> c = a[0,:].max() ##取第0行的最大值,其他行同理 >>> c 2
(8) Add columns to the array: np.hstack ()
n = np.array(np.random.randn(4,2)) n Out[153]: array([[ 0.17234 , -0.01480043], [-0.33356669, -1.33565616], [-1.11680009, 0.64230761], [-0.51233174, -0.10359941]]) l = np.array([1,2,3,4]) l Out[155]: array([1, 2, 3, 4]) l.shape Out[156]: (4,)As you can see, n is two-dimensional and l is one-dimensional. If you call np.hstack( directly ) will give an error: the dimensions are different.
n = np.hstack((n,l)) ValueError: all the input arrays must have same number of dimensions
The solution is to change l into two-dimensional, you can use the method in (5):
n = np.hstack((n,l[:,np.newaxis])) ##注意:在使用np.hstack()时必须用()把变量括起来,因为它只接受一个变量 n Out[161]: array([[ 0.17234 , -0.01480043, 1. ], [-0.33356669, -1.33565616, 2. ], [-1.11680009, 0.64230761, 3. ], [-0.51233174, -0.10359941, 4. ]])Let’s talk about how to add values to an empty list by column:
n = np.array([[1,2,3,4,5,6],[11,22,33,44,55,66],[111,222,333,444,555,666]]) ##产生一个三行六列容易区分的数组 n Out[166]: array([[ 1, 2, 3, 4, 5, 6], [ 11, 22, 33, 44, 55, 66], [111, 222, 333, 444, 555, 666]]) sample = [[]for i in range(3)] ##产生三行一列的空列表 Out[172]: [[], [], []] for i in range(0,6,2): ##每间隔一列便添加到sample中 sample = np.hstack((sample,n[:,i,np.newaxis])) sample Out[170]: array([[ 1., 3., 5.], [ 11., 33., 55.], [ 111., 333., 555.]])Continuously updating...Related recommendations:
Python NumPy library installation and usage notes
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