Ajax way to update nodes in xml

This time I will bring you the ajax method of updating nodes in xml. What are the precautions for updating nodes in xml with ajax? The following is a practical case, let's take a look.

Update the instance code of the node in xml

/* System.out.println("2323");
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder docbuilder = factory.newDocumentBuilder();
Document parse = docbuilder
.parse(new File("src/ProdQuery.xml"));
// Element createElement2 = parse.createElement("");
Element createElement = parse.createElement("products");
Node item2 = parse.getChildNodes().item(parse.getChildNodes().getLength()-1);
for (String item : map.keySet()) {
//循环添加至products
System.out.println("tianjia1");
Element clidren = parse.createElement("product");
Attr createAttribute = parse.createAttribute("name");
createAttribute.setNodeValue(item);
Attr createAttribute2 = parse.createAttribute("value");
createAttribute2.setNodeValue(map.get(item));
clidren.setAttributeNode(createAttribute);
clidren.setAttributeNode(createAttribute2);
createElement.appendChild(clidren);
}
//将products添加到根目录
item2.appendChild(createElement);
//创建一个TransformerFactory对象
TransformerFactory tFactory = TransformerFactory.newInstance();
//得到一个操作对象
Transformer transformer = tFactory.newTransformer();
//设置们，这个是编码
transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
//
DOMSource source = new DOMSource(parse);
System.out.println("改变文件");
StreamResult result = new StreamResult(new File("src/ProdQuery.xml"));
//让xml文件换行
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
transformer.transform(source, result);*/

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to php Other related articles on the Chinese website!

Recommended reading:

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