How to use ajax to implement pop-up login

This time I will show you how to use ajax to realize pop-up window login, and what are the precautions for using ajax to realize pop-up window login. The following is a practical case, let's take a look.

The following describes how to implement AJAX pop-up login.

In user.PHP in ECSHOP, there is a request to handle

user login.

/* 处理 ajax 的登录请求 */ 
elseif ($action == 'signin') 
{ 
 include_once('includes/cls_json.php'); 
 $json = new JSON; 
 $username = !empty($_POST['username']) ? json_str_iconv(trim($_POST['username'])) : ''; 
 $password = !empty($_POST['password']) ? trim($_POST['password']) : ''; 
 $captcha = !empty($_POST['captcha']) ? json_str_iconv(trim($_POST['captcha'])) : ''; 
 $result = array('error' => 0, 'content' => ''); 
 $captcha = intval($_CFG['captcha']); 
 if (($captcha & CAPTCHA_LOGIN) && (!($captcha & CAPTCHA_LOGIN_FAIL) || (($captcha & CAPTCHA_LOGIN_FAIL) && $_SESSION['login_fail'] > 2)) && gd_version() > 0) 
 { 
  if (empty($captcha)) 
  { 
   $result['error'] = 1; 
   $result['content'] = $_LANG['invalid_captcha']; 
   die($json->encode($result)); 
  } 
  /* 检查验证码 */ 
  include_once('includes/cls_captcha.php'); 
  $validator = new captcha(); 
  $validator->session_word = 'captcha_login'; 
  if (!$validator->check_word($_POST['captcha'])) 
  { 
   $result['error'] = 1; 
   $result['content'] = $_LANG['invalid_captcha']; 
   die($json->encode($result)); 
  } 
 } 
 if ($user->login($username, $password)) 
 { 
  update_user_info(); //更新用户信息 
  recalculate_price(); // 重新计算购物车中的商品价格 
  $smarty->assign('user_info', get_user_info()); 
  $ucdata = empty($user->ucdata)? "" : $user->ucdata; 
  $result['ucdata'] = $ucdata; 
  $result['content'] = $smarty->fetch('library/member_info.lbi'); 
 } 
 else 
 { 
  $_SESSION['login_fail']++; 
  if ($_SESSION['login_fail'] > 2) 
  { 
   $smarty->assign('enabled_captcha', 1); 
   $result['html'] = $smarty->fetch('library/member_info.lbi'); 
  } 
  $result['error'] = 1; 
  $result['content'] = $_LANG['login_failure']; 
 } 
 die($json->encode($result)); 
}

Modify the above code and delete the part that requires verification code

and change it to

/* 处理 ajax弹窗登录请求 */ 
elseif ($action == 'ajax_login') 
{ 
 include_once('includes/cls_json.php'); 
 $json = new JSON; 
 $username = !empty($_POST['username']) ? json_str_iconv(trim($_POST['username'])) : ''; 
 $password = !empty($_POST['password']) ? trim($_POST['password']) : ''; 
 $result = array('error' => 0, 'content' => ''); 
 $captcha = intval($_CFG['captcha']); 
 if ($user->login($username, $password)) 
 { 
  update_user_info(); //更新用户信息 
  recalculate_price(); // 重新计算购物车中的商品价格 
  $smarty->assign('user_info', get_user_info()); 
  $ucdata = empty($user->ucdata)? "" : $user->ucdata; 
  $result['ucdata'] = $ucdata; 
  $result['content'] = $smarty->fetch('library/member_info.lbi'); 
 } 
 else 
 { 
  $result['error'] = 1; 
  $result['content'] = $_LANG['login_failure']; 
 } 
 die($json->encode($result)); 
}

Change

// 不需要登录的操作或自己验证是否登录（如ajax处理）的act 
$not_login_arr = 
array('login','act_login','register','act_register','act_edit_password','get_password','send_pwd_email','password', 'signin', 'add_tag', 'collect', 'return_to_cart', 'logout', 'email_list', 'validate_email', 'send_hash_mail', 'order_query', 'is_registered', 'check_email','clear_history','qpassword_name', 'get_passwd_question', 'check_answer');

to

// 不需要登录的操作或自己验证是否登录（如ajax处理）的act 
$not_login_arr = 
array('ajax_login','login','act_login','register','act_register','act_edit_password','get_password','send_pwd_email','password', 'signin', 'add_tag', 'collect', 'return_to_cart', 'logout', 'email_list', 'validate_email', 'send_hash_mail', 'order_query', 'is_registered', 'check_email','clear_history','qpassword_name', 'get_passwd_question', 'check_answer');

common.js file,

In the openLginp() method, modify the HTML code of newp.innerHTML and add an ajaxLoginSubmit() method to the login box label.

//生成层内内容 
 newp.innerHTML = '<form id="ajax_loginForm">用户名：<br><input type="text" name="username" id="ajax_username"/>密码：<br><input type="password" name="password" id="ajax_password"/><br><br><button type="button" onclick="ajaxLoginSubmit()">登录</button> <button type="button" onclick="closeLoginForm()">关闭</button></form>';

Just write two more methods by yourself

function ajaxLoginSubmit(){ 
 var username = document.getElementById('ajax_username').value; 
 var password = document.getElementById('ajax_password').value; 
 Ajax.call('user.php?act=ajax_login','username='+username+'&password='+password,ajaxLoginResponse,'POST','JSON'); 
} 
function ajaxLoginResponse(result){ 
 if(result.error == 0){ 
  alert('登录成功'); 
 }else{ 
  alert('登录失败'); 
 } 
 return false; 
}

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!

Recommended reading:

Detailed explanation of ajax three-level linkage graphic and text (with code)

Detailed explanation of the basics and login steps of Ajax

The above is the detailed content of How to use ajax to implement pop-up login. For more information, please follow other related articles on the PHP Chinese website!