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python calls by instance method nameMar 29, 2018 pm 01:33 PM
pythonnamemethod

This article mainly introduces in detail how Python calls methods through instance method names. It has certain reference value. Interested friends can refer to it. I hope it can help everyone.

Case:

In a certain project, our code uses graphic classes from two different libraries:

Circle,Triangle

There is a method interface for obtaining area in these two categories, but the names of the interface are different

#:

uniform these interfaces, do not care about specific specifics, do not care about specific specifics, do not care about specific specifics, do not care about specific specifics, do not care about specific specifics. interface, as long as I call the unified interface, the corresponding area will be calculated.

How to solve this problem?

Define a unified interface function and call the interface through reflection: getattr

#!/usr/bin/python3
 
from math import pi
 
 
class Circle(object):
  def __init__(self, radius):
    self.radius = radius
 
  def getArea(self):
    return round(pow(self.radius, 2) * pi, 2)
 
 
class Rectangle(object):
  def __init__(self, width, height):
    self.width = width
    self.height = height
 
  def get_area(self):
    return self.width * self.height
 
 
# 定义统一接口
def func_area(obj):
  # 获取接口的字符串
  for get_func in ['get_area', 'getArea']:
    # 通过反射进行取方法
    func = getattr(obj, get_func, None)
    if func:
      return func()
   
 
if __name__ == '__main__':
  c1 = Circle(5.0)
  r1 = Rectangle(4.0, 5.0)
   
  # 通过map高阶函数,返回一个可迭代对象
  erea = map(func_area, [c1, r1])
  print(list(erea)) 

Call through the methodcaller method in the standard library operator

#!/usr/bin/python3
 
from math import pi
from operator import methodcaller
 
 
class Circle(object):
  def __init__(self, radius):
    self.radius = radius
 
  def getArea(self):
    return round(pow(self.radius, 2) * pi, 2)
 
 
class Rectangle(object):
  def __init__(self, width, height):
    self.width = width
    self.height = height
     
  def get_area(self):
    return self.width * self.height
 
if __name__ == '__main__':
  c1 = Circle(5.0)
  r1 = Rectangle(4.0, 5.0)
   
  # 第一个参数是函数字符串名字,后面是函数要求传入的参数,执行括号中传入对象
  erea_c1 = methodcaller('getArea')(c1)
  erea_r1 = methodcaller('get_area')(r1)
  print(erea_c1, erea_r1)

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