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What should I do if there is no reflection after successful ajax request for background data?

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php中世界最好的语言Original
2018-03-15 14:28:282974browse

This time I will bring you how to deal with the problem of no reflection after the ajax request for background data is successful. What are the things to note ? The following is a practical case. Let’s take a look. . After the ajax request for background data in

jquery succeeds, neither success nor error is executed. In addition, the system reports an error: Uncaught SyntaxError: Unexpected identifier at Object.success, but The background can return data. The original code is as follows:

 var source=[];
$.ajax({   
  type: "post",   
  url: "connectdb/select.jsp",    
  data: {database: "scmdb", selectsql: sql}, 
  async: false, method: 'post',  
  dataType: "json", 
  success: function(data) {   
    eval("source="+data+";");
    //source=eval(data); 
    alert("正确");
  },
  error: function(err) {  
    alert("错误");   
  }
});
return source;  
The main reason is that the data returned by the background is not in json format, and dataType: "json" is specified in the code. The solution is to change json to text. After modification The code is as follows:

 var source=[];
$.ajax({   
  type: "post",   
  url: "connectdb/select.jsp",    
  data: {database: "scmdb", selectsql: sql}, 
  async: false, method: 'post',  
  dataType: "text", 
  success: function(data) {   
    eval("source="+data+";");
    //source=eval(data); 
    alert("正确");
  },
  error: function(err) {  
    alert("错误");   
  }
});
return source;

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the PHP Chinese website!

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