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How to update database data in PHP

小云云
小云云Original
2018-03-09 11:45:3410297browse

This article mainly shares with you how to update database data in PHP. Hope it helps everyone.

The first step is to create the update page file Upwork.php

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>删除</title>
</head>
<body>
<h1 style=&#39;font-size:18px;text-align:center;&#39;>修改数据</h1>
  <?php
  $code = $_GET["code"];
  $db = new MySQLi("localhost","root","123456","study");
  !mysqli_connect_error() or die("连接失败！");
  $sql1 = "select * from `员工信息` where 工号=&#39;{$code}&#39;";
  $r1 = $db->query($sql1);
  $att1 = $r1->fetch_row();
 ?>
 <form action="UpworkChuLi.php" method="post">
 <p style=&#39;text-align:center;&#39;>
     <p style=&#39;margin:10px;&#39;>员工工号：<input readonly="readonly" name="code" value="<?php echo $att1[0];?>" /></p>
     <p style=&#39;margin:10px;&#39;>员工姓名：<input type="text" name="name" value="<?php echo $att1[1];?>" /></p>
<p style=&#39;margin:10px;&#39;>出生日期：<input type="text" name="date" value="<?php echo $att1[2];?>"></p>
<p style=&#39;margin:10px;&#39;>员工年龄：<input type="text" name="age" value="<?php echo $att1[3];?>" /></p>
     <p style=&#39;margin:10px;&#39;>员工职称：<input type="text" name="job" value="<?php echo $att1[4];?>" /></p>
<p style=&#39;margin:10px;&#39;>所在部门：<input type="text" name="department" value="<?php echo $att1[5];?>"></p>
<p style=&#39;margin:10px;&#39;>员工月薪：<input type="text" name="month" value="<?php echo $att1[6];?>" /></p>
     <p style=&#39;margin:10px;&#39;>员工年薪：<input type="text" name="year" value="<?php echo $att1[7];?>" /></p>
<p style=&#39;margin:10px;&#39;>政治面貌：<input type="text" name="politics" value="<?php echo $att1[8];?>"></p>
<p style=&#39;margin:10px;&#39;>健康状况：<input type="text" name="health" value="<?php echo $att1[9];?>"></p>
    
     <p><input type="submit" value="修改数据" /></p>
</p>
 </form>
</body>

73a6ac4ed44ffec12cee46588e518a5e

The second step is to create the update data operation file UpworkChuLi.php, Jump through the form in Upwork.php

<?php
$code = $_POST["code"];
$name = $_POST["name"];
$date  = $_POST["date"];
$age = $_POST["age"];
$job = $_POST["job"];
$department = $_POST["department"];
$month = $_POST["month"];
$year = $_POST["year"];
$politics = $_POST["politics"];
$health = $_POST["health"];
 $db = new MySQLi("localhost","root","123456","study");
 !mysqli_connect_error() or die("连接失败！");
 $sql = "update `员工信息` set 姓名=&#39;{$name}&#39;,出生日期=&#39;{$date}&#39;,年龄=&#39;{$age}&#39;,职称=&#39;{$job}&#39;,
 所在部门=&#39;{$department}&#39;,月薪=&#39;{$month}&#39;,年薪=&#39;{$year}&#39;,政治面貌=&#39;{$politics}&#39;,健康状况=&#39;{$health}&#39; 
 where 工号=&#39;{$code}&#39;";
 $r = $db->query($sql);
 if($r)
 {
     header("location:work.php");
 }
 else
 {
     echo "修改失败！";
 }
?>

Related recommendations:

Five ways to update the database in thinkphp.

php Solution to update database interruption_PHP tutorial

php+mysqli uses object-oriented method to update database instance, mysqli object-oriented_PHP Tutorial

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