digui($i-1); for($j=1;$j"/> digui($i-1); for($j=1;$j">
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public function digui($i) { if($i=='1'){ echo "*" ; echo "<br>"; return ; }else{ $this->digui($i-1); for($j=1;$j<=$i;$j++){ echo "*" ; } echo "<br>"; } } 调用 $this->digui(3); 结果 * ** *** function digui2($n){ echo $n." "; if($n>0){ $this-> digui2($n-1); }else{ echo "<-->"; } echo $n." "; }
Call $this->digui2(3);
Result
3 2 1 0 71fb34173e4ee87dab1f85dc1c283a440 1 2 3
Recursive function execution anatomy example (reposted from others)
Look at the following code:
<?php function one($num){ echo $num; two($num-1); echo $num; } function two($num){ echo $num; three($num-1); echo $num; } function three($num){ echo $num; } one(3); ?>
The above code decomposes the test() function. We Thinking:
When executing the one(3) function, like the test() function, first output 3, and then call the two(2) function,
Note that the following 3 has not been output at this time,
Go on, execute the two(2) function, output 2, and call the three(1) function. Similarly, there is no time to output the following 2,
Execute three(1), output 1 directly, and no longer call other functions,
At this time, we wonder if the two() function just has not been executed yet. OK, then execute the unfinished part of the two() function. After the two() function is executed, the following 2 is output, and then starts Execute the unfinished part of the one() function, that is, output the following 3. At this time, all functions have been executed.
Then, the output result is:
3 2 1 2 3
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