js example of determining whether a number is an nth power of 2

Method 1

How to determine whether a number is 2 raised to the nth power? The simple way to determine is to directly divide the number num by 2. If the remainder is 0, Then divide num/2 by 2, and then determine whether the remainder is 0. If so, continue with the previous step until num=1 in the end.

For example:

2 2%2=0 (2/2)=1 is

4 4%2=0 (4/2 )%2=0 (4/2/2)=1 Yes

6 6%2=0 (6/2)%2=1 No

7 7%2=1 No

24 24%2=0 (24/2)%2=0 (24/2/2)%2=0 (24/2/2/2)%2=1 Not

Code implementation:

function check(num){
 if(num != 1){
  while(num != 1){
   if(num%2 == 0){
    num = num / 2;
   }else{
    return false;
   }

  }
  return true;
 }else{
  return true;
 }
}

##The results are as follows:

Method 2

Using the binary method, you can determine whether a number num is the nth power of 2. The rules can be known , as long as it is a power of 2, the highest bit must be 1 and the rest are 0. When num-1, the highest bit is 0 and the rest are 1.

Bitwise AND operation: 1&1=1 0&1=0 0&0=0 1&0=0

2                                                                          6 ---> 110

8 ---> 1000 7 ---> 111

Example:

#8 Binary 1000 8-1 Binary 0111 Press Bitwise AND operation 1000&0111 --> 0000 So 8 is 2 raised to the nth power.

9 The binary system 1001 The binary system 1000 of 9-1 Bitwise AND operation 1001&1000 ---> 1000 So 9 is not a power of 2.

24’s binary 11000 24-1’s binary 10111 Bitwise AND operation 11000&10111 ---> 10000 So 24 is not a power of 2.

You can write the binary number of num through num.toString(2).

Code implementation:

##

function check(num){
 return (num > 0) && ((num & (num - 1)) == 0);
}

The results are as follows:

The other 1 is also the 0th power of 2.

There are other conditions not written out. This method is to judge whether a number is the nth power of 2. It does not write out whether the number is an integer. If possible, add conditional judgment by yourself.

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