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python basic syntax

巴扎黑
巴扎黑Original
2017-09-21 10:48:191796browse

The following editor will bring you an example of python basic grammar practice. The editor thinks it’s pretty good, so I’ll share it with you now and give it as a reference. Let’s follow the editor to take a look.

1. Print the multiplication table


#只打印结果
for i in range(1,10):
  for j in range(1,i+1):
    print(i*j,end=" ")
  print()
 
#打印算数表达式
for i in range(1,10):
  for j in range(1,i+1):
    print("{0}*{1} = {2:2}".format(j,i,i*j),end=" ")
    print()
 
1*1 = 1 
1*2 = 2 2*2 = 4 
1*3 = 3 2*3 = 6 3*3 = 9 
1*4 = 4 2*4 = 8 3*4 = 12 4*4 = 16 
1*5 = 5 2*5 = 10 3*5 = 15 4*5 = 20 5*5 = 25 
1*6 = 6 2*6 = 12 3*6 = 18 4*6 = 24 5*6 = 30 6*6 = 36 
1*7 = 7 2*7 = 14 3*7 = 21 4*7 = 28 5*7 = 35 6*7 = 42 7*7 = 49 
1*8 = 8 2*8 = 16 3*8 = 24 4*8 = 32 5*8 = 40 6*8 = 48 7*8 = 56 8*8 = 64 
1*9 = 9 2*9 = 18 3*9 = 27 4*9 = 36 5*9 = 45 6*9 = 54 7*9 = 63 8*9 = 72 9*9 = 81
 
#将打印矩阵转置一下
for i in range(1,10):
  print(" " *10*(i-1), end = " ")
  for j in range(i,10):
    print("{0}*{1} = {2:<2}".format(i,j,i*j),end=" ")
  print()
   
 1*1 = 1  1*2 = 2  1*3 = 3  1*4 = 4  1*5 = 5  1*6 = 6  1*7 = 7  1*8 = 8  1*9 = 9 
      2*2 = 4  2*3 = 6  2*4 = 8  2*5 = 10 2*6 = 12 2*7 = 14 2*8 = 16 2*9 = 18 
           3*3 = 9  3*4 = 12 3*5 = 15 3*6 = 18 3*7 = 21 3*8 = 24 3*9 = 27 
                4*4 = 16 4*5 = 20 4*6 = 24 4*7 = 28 4*8 = 32 4*9 = 36 
                     5*5 = 25 5*6 = 30 5*7 = 35 5*8 = 40 5*9 = 45 
                          6*6 = 36 6*7 = 42 6*8 = 48 6*9 = 54 
                               7*7 = 49 7*8 = 56 7*9 = 63 
                                    8*8 = 64 8*9 = 72 
                                         9*9 = 81

2. Print a diamond (the number of lines is an odd number)


for i in range(-3,4):
  prespace=(-i if i<0 else i)
  print(" "*prespace + &#39;*&#39;*(7-2*prespace))
 
  *
 ***
 *****
*******
 *****
 ***
  *
 
 
 
#变形之打印一道闪电
while True:
  line_max = int(input("please input a odd number: "))
  if line_max % 2:
    break
range_num = (line_max + 1)//2
 
for i in range(-range_num+1,range_num):
  if i == 0:
    print(&#39;*&#39;*line_max)
  elif i > 0:
    print(&#39; &#39;*(range_num-1) + "*"*(range_num-i))
  else:
    print(&#39; &#39;*(-i) + &#39;*&#39;*(range_num+i))
 
  *
 **
 ***
*******
  ***
  **
  *
 
#变形之打印掏空的菱形
for i in range(-4,5):
  if i == -4 or i == 4:
    print(&#39;*&#39;*9)
  else:
    prespace=(-i+1 if i<0 else i+1)
    print("*"*prespace + &#39; &#39;*(9-2*prespace) + "*"*prespace)
 
*********
**** ****
***  ***
**   **
*    *
**   **
***  ***
**** ****
*********

3. Print within 100 The Fibonacci sequence


f0, f1 = 0, 1
while f1 <= 100:
  print(f1, end = " ")
  t = f1
  f1 = t + f0
  f0 = t

I don’t understand how to write it yet:


f0, f1 = 0, 1
while f1 <= 100:
  print(f1)
  f0, f1 = f1, f0 + f1 #python对这样的赋值怎样处理

4. Find the 101st term of the Fibonacci sequence


##

f0, f1 = 0, 1
for i in range(3,102):
  t = f1
  f1 = t + f0
  f0 = t
else:
  print(f1)

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