C++ functions and pointers

I am reading C++ Primer Plus recently, and I feel that the chapter of functions and pointers is more difficult. Take notes to enhance your understanding.

From C++ Primer Plus: Chapter 7 Function:C++ Programming Modules

1. How to declare function pointer?

Similar to the function prototype: you need to declare the pointer pointing to the return value and parameter list of the function

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double pam(int); //参数为int 类型，返回值为double 类型的函数
double (*pf);(int)  //指向参数为int类型,返回值为double 类型的指针
pf = pam;   //函数名代表了函数的地址

double x = pam(4); //函数名调用
double x = (*pf)(4); //指针调用
double x = pf(4); //C++也允许将指针名当作函数名使用

2. C++ 11 automatic typing Inference

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 const double * f1(const double *, int);
 const double * (*p1)(const double *, int); //p1 poitns to f1
 auto p2 = f1; //C++11 automatic type deduction,p2 points to f1 as well

3. Use pointer name as function name

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//前面函数为double *类型，cout第一部分返回double指针，第二部分返回double指针指向的值
cout<<(*p1)(av,3)<<":"<<*(*p1)(av,3)<<endl;
//和上面的cout一样只不过是使用函数指针名来调用函数
cout<<p2(av,3)<<":"<<*p2(av,3)<<endl;

4 . Function pointer array

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const double *(*pa[3]) (const double *,int) = {f1,f2,f3}; //创建函数指针数组
//通过指针调用函数，得到返回的指针
const double *px = pa[0](av,3); //call by pointer as if it were a function name
const double *py = (*pa[0])(av,3); //正常调用

//得到函数返回指针指向的值
double x = *pa[0](av,3);
double x = *(*pa[0])(av,3);

5. Pointer to pointer array

The difference between pointer array and array pointer

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*pd[3] //an array of 3 pointers
(*pd)[3] //a pointer to an array of three elements

Pointer to array

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1 auto pc = &pa; //&pa is the entire array The address, pa is the first address of the first element of the array

2

3 const double * (*(*pd)[3])(const double *, int ) = &pa; / /Equivalent to the first

4

5 **&pa = *pa = pa[0]

Code:

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//arfupt.cpp -- an array of function pointers
#include<iostream>
//various notations,same signatures
const double *f1(const double ar[],int n);
const double *f2(const double [],int);
const double *f3(const double *,int);

int main()
{
    using namespace std;
    double av[3] = {1112.3,1542.6,2227.9};

    //pointer to a function

    const double *(*p1)(const double *,int) = f1;
    auto p2 = f2;//C++ 11 utomatic  type deduction
    //pre-C++11 can use the following code instead
    //const double *(*p2)(const double *,int) = f2;
    cout<<"Using pointers to functions:\n";
    cout<<"Address Value\n";
    cout<<(*p1)(av,3)<<":"<<*(*p1)(av,3)<<endl;
    cout<<p2(av,3)<<":"<<*p2(av,3)<<endl;

    //pa an array of pointers
    //auto doesn&#39;t work with list initialization
    const double *(*pa[3])(const double *,int) = {f1,f2,f3};
    //pb a pointer to first element of pa
    auto pb = pa;
    // pre-C++11 can use the following code instead
    // const double *(**pb)(const double *, int) = pa;
    cout<<"\nUsing an array of pointers to functions:\n";
    cout<<"Address Value\n";
    for(int i = 0;i < 3; i++)
        cout<<pa[i](av,3)<<":"<<*pa[i](av,3)<<endl;
    cout<<"\nUsing a pointer to a pointer to a function:\n";
    cout<<"Address Value\n";
    for(int i = 0;i < 3; i++)
        cout<<pb[i](av,3)<<":"<<*pb[i](av,3)<<endl;

    //what about a pointer to an array of function pointers
    cout<<"\nUsing pointers to an array of pointers:\n";
    cout<<"Address Value\n";
    //easy way to declare pc
    auto pc = &pa;
    // pre-C++11 can use the following code instead
    // const double *(*(*pc)[3])(const double *, int) = &pa;
    cout<<(*pc)[0](av,3)<<":"<<*(*pc)[0](av,3)<<endl;
    //hard way to declare pd
    const double *(*(*pd)[3])(const double *,int) = &pa;
    //store return value in pdb
    const double *pdb = (*pd)[1](av,3);
    cout<<pdb<<":"<<*pdb<<endl;
    //alternative notation
    cout<<(*(pd)[2])(av,3)<<":"<<*(*(*pd)[2])(av,3)<<endl;
}

const double * f1(const double * ar, int n)
{
return ar;
}
const double * f2(const double ar[], int n)
{
return ar+1;
}
const double * f3(const double ar[], int n)
{
return ar+2;
}

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