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Home >Web Front-end >JS Tutorial >Detailed explanation of problems that occur when uploading ajaxfileupload
1. The following problems will occur when uploading ajaxfileupload:
2. There are many solutions on the Internet. Here, I found another one, maybe your error will be caused by this reason
------The reason is: You do not need to return to the foreground in the general handler Data format string
3. An example is given below:
前台: <style type="text/css"> .fileLink{position: relative;display: inline-block;background: #fff; border: 1px solid #0980D0;border-radius: 4px; padding: 2px 8px;margin-left:10px;margin-top:10px;overflow: hidden;color: #1E88C7;text-decoration: none;text-indent: 0;line-height: 20px;} 4 .fileLink input {position: absolute;font-size: 100px;right: 0;top: 0;opacity: 0;} 5 .fileLink:hover {background: #AADFFD;border-color: #78C3F3; cursor:pointer;color: #004974;text-decoration: none;} 6 </style> 7 <span class="fL fileLink" style="padding-left: 10px;">选择文件<input type="file" id="uploadify" name="uploadify" value="上传数据" /></span> 8 <script src="../../Plugins/jquery/jquery-1.7.2.min.js?1.1.11" type="text/javascript"></script> 9 <script src="../../Plugins/ajaxfileupload.js?1.1.11" type="text/javascript"></script>10 11 <script>12 $("#uploadify").on("change", function () {13 //var file = $("#uploadify")[0].files[0];14 $.ajaxFileUpload({15 url: './ImportDynamic.ashx',16 fileElementId: 'uploadify',17 dataType: 'text',18 success: function (data, status) {19 alert(1);20 },21 error: function () { }22 });23 }); </script>25 26 一般处理程序:27 context.Response.ContentType = "text/plain";28 var filePath = "uploadfile/xxx.xls";29 filePath = context.Server.MapPath(filePath);30 Import.GetCommonReportFile(filePath);31 //context.Response.Write("返回文本数据,否则前台就会报如上错误");
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