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To implement a constructor is two variables , and the other constructor is an array .
For example:
public function construct($id, $dname) public function construct($device=array())
I only found on the Internet that it can be implemented by judging the number of parameters through func_num_args. Is there any way to implement it by judging the type?
It is impossible to have two method functions with the same name in one file at the same time
2. If they are in different files, you can use namespace to implement the same function Call (php version must be 5.3.0 or above)
So your judgment has no real meaning
PHP cannot be overloaded, change the parameters to an array and make the difference within the function
I Want to see how they coexist in the source code, inheritance?
gettype -- Get the type of the variable
construct is not the constructor of the php class
construct is!
Although php does not support overloading, the poster did not say that it is a method with the same name in a class
Judge the parameter type in the constructor construct, and then take different branches That's it. If you don’t support overloading natively, just simulate it~
php does not support function overloading like C. Just like you said, use the func_num_arg function and then judge the parameters to branch initialization
You can determine the number and type of parameters in construct.
<?php class demo{ private $_args; public function construct(){ $args_num = func_num_args(); if($args_num==2){ $this->_args = array( 'id' => func_get_arg(0), 'dname' => func_get_arg(1) ); }elseif($args_num==1 && is_array(func_get_arg(0))){ $this->_args = array( 'device'=>func_get_arg(0) ); }else{ exit('func param not match'); } } public function show(){ echo '<pre class="brush:php;toolbar:false">'; print_r($this->_args); echo ''; } } // demo1 $id = 1; $dname = 'fdipzone'; $obj = new demo($id, $dname); $obj->show(); // demo2 $device = array('iOS','Android'); $obj = new demo($device); $obj->show(); ?>
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