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jdk1.7.0_79
## The above explains the relevant# The source code of several common methods in ##ArrayList- "Source code analysis of common methods in ArrayList", this article will briefly describe the common methods in LinkedList Parse . LinkedList
is implemented based on a linked list, which means that it has the advantages and disadvantages of a linked list, with slow random access and fast insertion and deletion speeds. Since it is a linked list, it has a node data structure, and there is no problem of capacity. Just add one at the end.
//LinkedList$Nodeprivate static class Node<E> { E item; Node<E> next; Node<E> prev; Node(Node<E> prev, E element, Node<E> next) {this.item = element;this.next = next;this.prev = prev; } }
//1.LinkedList,默认构造方法public LinkedList() { }
.
//2.LinkedList,能将一个集合作为参数的构造方法public LinkedList(Collection<? extends E> c) {this(); addAll(c); }
public boolean add(E e) { linkLast(e); //将元素添加到链表尾部return true; }
//LinkedList#linkLastvoid linkLast(E e) {final Node<E> l = last; //链表尾指针引用暂存final Node<E> newNode = new Node<>(l, e, null); //构造新节点last = newNode; //将链表的尾指针指向新节点if (l == null) //此时为第一次插入元素first = newNode;elsel.next = newNode; size++; //链表数据总数+1modCount++; //modCount变量在《有关ArrayList常用方法的源码解析》提到过,增删都会+1,防止一个线程在用迭代器遍历的时候,另一个线程在对其进行修改。}
method.
//LinkedList#removepublic E remove(int index) { checkElementIndex(index); //检查是否越界 index >= 0 && index <= sizereturn unlink(node(index)); //调用node方法查找并返回指定索引位置的Node节点}
//LinkedList#node,根据索引位置返回Node节点Node<E> node(int index) {if (index < (size >> 1)) { //size >> 1 = size / 2,如果索引位于链表前半部分,则移动fisrt头指针进行查找Node<E> x = first;for (int i = 0; i < index; i++) x = x.next;return x; } else { //如果索引位于链表后半部分,则移动last尾指针进行查找Node<E> x = last;for (int i = size - 1; i > index; i--) x = x.prev;return x; } }
position After ##Node, call the unlink method to remove the node. //LinkedList#unlink,一看即懂E unlink(Node<E> x) {// assert x != null;final E element = x.item;final Node<E> next = x.next;final Node<E> prev = x.prev;if (prev == null) {
first = next;
} else {
prev.next = next;
x.prev = null;
}if (next == null) {
last = prev;
} else {
next.prev = prev;
x.next = null;
}
x.item = null;
size--;
modCount++;return element;
}
and ArrayList from the code, since only a simple linked list data structure is involved, other methods will not be parsed.
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