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Introduction and usage of Fork/Join appearing in java7

零下一度
零下一度Original
2017-06-25 10:42:261965browse

Fork/Join

The Fork/Join that appears in JAVA7 is similar to the mapreduce idea of ​​the distributed file system hadoop, which is to divide the task and then divide it until the conditions are met

In order to facilitate understanding: programming logic can borrow the idea of ​​recursion, recurse layer by layer until the final call is encountered, and then return layer by layer; in Fork/Join, it is similar to placing each recursive method in a separate thread. Medium;

Make full use of modern multi-core processors to process tasks in parallel

Such as:

 

/**
 * 继承RecursiveTask 则每个子任务带返回值
 * 继承RecursiveAction 则每个子任务不带返回值 */public class FockJoin1 extends RecursiveTask<Integer>{public static void main(String[] args) throws ExecutionException, InterruptedException {long l = System.currentTimeMillis();
        ForkJoinPool pool = new ForkJoinPool();                         //类似线程池,也实现了AbstractExecutorServiceFockJoin1 task = new FockJoin1(1,1000000000);         //新建任务Future<Integer> result = pool.submit(task);                     //将任务提交System.out.println("result is" + result.get());                 //获取结果System.err.println(System.currentTimeMillis() - l);
    }private final Integer index = 5000; //分割任务的基数private final Integer left;private final Integer right;public FockJoin1(Integer left, Integer right) {this.left = left;this.right = right;
    }
    
    @Overrideprotected Integer compute() {int sum = 0;if(right - left < index) {                      //如果任务 小于基数,则直接执行;类似递归的出口for (int i = left; i <= right; i++) {
                sum += i;
            }
        }else {                                         //任务 大于基数,则分割,类似与二分法,也可以更多int middle = (right + left) >> 1;
            FockJoin1 myf1 = new FockJoin1(left, middle);           //二分法左边FockJoin1 myf2= new FockJoin1(middle+1, right);    //二分法右边myf1.fork();                                            //继续执行,类似递归myf2.fork();                                            //继续执行,类似递归Integer integer1 = myf1.join();                         //等待Integer integer2 = myf2.join();
            sum = integer1 + integer2;                              //结果合并        }return sum;
    }
}

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