


Detailed explanation of how to perfectly implement JavaScript to return the date of the previous month for a given date
这篇文章主要介绍了javascript完美实现给定日期返回上月日期的方法,结合实例形式分析了javascript日期时间的计算技巧,并给出了格式化日期时间的操作方法,需要的朋友可以参考下
本文实例讲述了javascript完美实现给定日期返回上月日期的方法。分享给大家供大家参考,具体如下:
在项目开发中,使用javascript对日期进行处理时,因为在查询中都会有一个初始值,大多都会在当前日期的基础上推一个月,在这种情况下,如果自己写一个,需要考虑的情况较多,在这里给大家分享一下一个比较完善的解决这个问题的方法。供大家参考。例如:给定截止日期enddate=2010-07-31
计算得到开始日期startdate=2010-06-30
这个问题的关键在于对以下几处的考虑:
1、startdate跨年
2、startdate是2月(需考虑闰年的情况)
3、大小月
<html> <script type="text/javascript"> function getInitStartDate(enddate) { var comp = enddate.split("-"); var year = comp[0]; var month = comp[1]; var date = comp[2]; if (month == "01") { //前一月跨年 month = 12; year = year - 1; } else { month = month - 1; if (month == 2 && date > 28) { date = isLeapYear(year) ? 29 : 28; } else if (date == 31) { switch (month) { case 4: case 6: case 9: case 11: date = 30; break; default: break; } } } month = ("" + month).length == 1 ? ("0" + month) : ("" + month); var dateFormat = year + "-" + month + "-" + date; return dateFormat; } function isLeapYear(y) { //判断y是否为闰年 return (y % 4 == 0) && (y % 400 == 0 || y % 100 != 0); } alert(getInitStartDate("2010-07-31")); </script> </html>
配套给出一个格式化日期的方法:
<script language="JavaScript"> Date.prototype.format = function(format) //author: meizz { var o = { "M+" : this.getMonth()+1, //month "d+" : this.getDate(), //day "h+" : this.getHours(), //hour "m+" : this.getMinutes(), //minute "s+" : this.getSeconds(), //second "q+" : Math.floor((this.getMonth()+3)/3), //quarter "S" : this.getMilliseconds() //millisecond } if(/(y+)/.test(format)) format=format.replace(RegExp.$1, (this.getFullYear()+"").substr(4 - RegExp.$1.length)); for(var k in o)if(new RegExp("("+ k +")").test(format)) format = format.replace(RegExp.$1, RegExp.$1.length==1 ? o[k] : ("00"+ o[k]).substr((""+ o[k]).length)); return format; } alert(new Date().format("yyyy-MM-dd")); alert(new Date("january 12 2008 11:12:30").format("yyyy-MM-dd hh:mm:ss")); </script>
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