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Seamless carousel carousel

巴扎黑Original: 2017-06-26 15:01:121552browse

If the beginning and end cannot be connected when making carousel images, the effect will be a bit ugly. Here is a method I commonly use:

First explain in text:

If you want to display 5 pictures, respectively 1, 2, 3, 4, 5. Then the introduction of the code is like this: 1, 2, 3, 4, 5, 1

The order of rotation is here Not much to say, the main point is the carousel of 5>1 and 1>5

i represents the index of the current picture

pre represents the button of the previous picture

next represents the button for the next picture

ul represents the picture list

(1) 5>1>2... When the "next" button goes from 5 to 1, it rotates normally in order , when the current picture is the second "1", the next picture should be "2", then when it is "next", the left value of ul is 0, i==1;

(2 ) 1>5>4.... When the "pre" button rotates from the current picture "1" (the first 1) to picture 5, i==4, the left value of ul becomes -5 which is the width of img times, that is, let the first 1 quietly become the last 1;

It’s a bit confusing to express in language, here is the code:

<!DOCTYPE html>
<html lang="en">
<head>
	<meta charset="UTF-8">
	<title>Document</title>
	<style type="text/css">
		*{padding: 0;margin: 0;}
		.container{
			width: 273px;height: 163px;overflow: hidden;
			position: relative;margin: 0 auto;
		}
		.list{
			position: absolute;width: 1638px;top: 0;left: 0px;
		}
		.list li{
			float: left;list-style: none;
		}
		.btn{
			position: absolute;display: block;width: 40px;height: 50px;font-size: 40px;
			text-align: center;font-weight: bold;top: 50%;margin-top: -25px;background-color: rgba(255,255,255,0.5);cursor:pointer;
		}
		.btn:hover{
			background-color: rgba(0,0,0,0.3);color: #fff;
		}
		.pre{
			left: 0;
		}
		.next{
			right: 0;
		}
		.nav{
			position: absolute;bottom: 5px;display: flex;justify-content: center;width: 100%;
		}
		.nav span{
			width: 10px;height: 10px;border-radius: 10px;background-color: #fff;z-index: 2;display: inline-block;margin-right: 10px;cursor: pointer;
		}
		span.on{
			background-color: orange;
		}
	</style>
</head>
<body>
	<div class="container">
		<ul class="list" style="left: 0px">
			<li><img src="./images/1.png" alt=""></li>
			<li><img src="./images/2.png" alt=""></li>
			<li><img src="./images/3.png" alt=""></li>
			<li><img src="./images/4.png" alt=""></li>
			<li><img src="./images/5.png" alt=""></li>
			<li><img src="./images/1.png" alt=""></li>
		</ul>
		<div class="nav">
			<span class="on"></span>
			<span></span>
			<span></span>
			<span></span>
			<span></span>
		</div>
		<em class="next btn">></em>
		<em class="pre btn"><</em>
	</div>
	<script type="text/javascript" src="../jquery.js?1.1.11"></script>
	<script type="text/javascript">
		$(function(){
			var i=0;
			$(&#39;.next&#39;).click(function(){
				i++;
				console.log(i);

				moveImg(i);
				
			});
			$(&#39;.pre&#39;).click(function(){
				i--;
				moveImg(i);
				
			});
			$(&#39;.nav span&#39;).click(function(){
				var _index=$(this).index();
				i=_index;
				moveImg(i);

				
			});
			// i的作用：决定下一张图片是谁————也就是说ul的left是多少。
			// $(&#39;.list&#39;).css({left)的值是从图a过度是此时的ul的left。
			function moveImg(){
				if (i==6) {
					i=1;
					$(&#39;.list&#39;).css({&#39;left&#39;:&#39;0&#39;});
				}
				 // 是第一张
		        if(i==-1){
		            i=4;
		            $(&#39;ul&#39;).css({left:(5*-273)});
		        }
				$(&#39;.list&#39;).stop().animate({&#39;left&#39;:-273*i+&#39;px&#39;},1000);
				if (i==5) {
				$(&#39;.nav span&#39;).eq(0).addClass(&#39;on&#39;).siblings().removeClass(&#39;on&#39;);

				}
				$(&#39;.nav span&#39;).eq(i).addClass(&#39;on&#39;).siblings().removeClass(&#39;on&#39;);

			}
		})
	</script>
</body>
</html>

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