How to solve the problem when clicking on the bootstrap drop-down menu to hide it immediately

This article mainly introduces the method to solve the bug of immediately hiding the bootstrap drop-down menu when clicked. It has certain reference value. If you are interested, you can learn about it

Yesterday, I used jQuery and bootstrap to implement the drop-down menu check box. Today, I combined the completed demo into the project and found a bug. When clicking on the bank checkbox, the dropdown-menu p will be hidden immediately, which means that only one can be selected at a time.

This should be the reason for event propagation. The code is modified as follows:

var banks = $('.all').siblings().children();
$('.all>input').click(function() {
  var flag = $(this).prop('checked');
  banks.prop('checked', flag);
})

// 阻止事件传播, 否则在点击复选框的时候，dropdown-menu这个p会立即隐藏
$('.dropdown-menu label').click(function(e) {
  e.stopPropagation();
});
banks.click(function() {
  // 如果有一个没选中，全选按钮不选中
  // 如果全部选中，全选按钮被选中
  var num = 0;
  banks.each(function() {
    if ($(this).prop("checked")) {
      num++;
    }
  })
  if (num == banks.length) {
    $('.all>input').prop('checked', true);
  } else {
    $('.all>input').prop('checked', false);
  }
})

In addition, new The added function is that when clicking the "Save" button, the selected bank name needs to be concatenated with commas into a string and passed to the backend. This part is relatively simple, the code is as follows:

// 在提交时，获取选中的所有值，并把这些值拼接成字符串
$('.submit').click(function() {
  var bankArr = [];
  banks.each(function() {
    if ($(this).prop("checked")) {
      bankArr.push($(this).val());
    }
  });
  var bankStr = bankArr.join(',');
  console.log(bankStr);
})

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