Today is the last day of work. There is nothing to do. It just so happens that the students in the group are discussing the algorithm of group red envelopes.
A close-up of an algorithm. The general idea is to find red envelopes that have been distributed and find their random vibration slope.
Let’s take a look at the algorithm:
#coding=gbk import random import sys #print random.randint(0, 99) #print "====", random.uniform(0, 0.99) def calRandomValue(min, max, total, num): print min, max, total, num total = float(total) num = int(num) min = 0.01 if(num < 1): return if num == 1: print "第%d个人拿到红包数为:%.2f" %(num, total) return i = 1 total_money = total #rtotal = (total*100 - min*num*100)/100 while( i < num ): max = total_money - min*(num- i) k = int((num-i)/2) if num -i <= 2: k = num -i max = max/k monney = random.randint(int(min*100), int(max*100)) monney = float(monney)/100 total_money = total_money - monney print "第%d个人拿到红包数为:%.2f, 余额为: %.2f" %(i, monney, total_money) i += 1 print "第%d个人拿到红包数为:%.2f, 余额为: %.2f" %(i, total_money, 0.0) if __name__ == "__main__": min = sys.argv[1] max = sys.argv[2] total = sys.argv[3] num = sys.argv[4] calRandomValue(min, max, total, num)
Execution:
python 2.py 0.01 10 20 300.01 10 20 30第1个人拿到红包数为:0.42, 余额为: 19.58第2个人拿到红包数为:0.12, 余额为: 19.46第3个人拿到红包数为:0.24, 余额为: 19.22第4个人拿到红包数为:1.10, 余额为: 18.12第5个人拿到红包数为:1.45, 余额为: 16.67第6个人拿到红包数为:0.21, 余额为: 16.46第7个人拿到红包数为:0.34, 余额为: 16.12第8个人拿到红包数为:0.16, 余额为: 15.96第9个人拿到红包数为:1.38, 余额为: 14.58第10个人拿到红包数为:0.86, 余额为: 13.72第11个人拿到红包数为:1.18, 余额为: 12.54第12个人拿到红包数为:0.93, 余额为: 11.61第13个人拿到红包数为:0.70, 余额为: 10.91第14个人拿到红包数为:0.60, 余额为: 10.31第15个人拿到红包数为:0.03, 余额为: 10.28第16个人拿到红包数为:0.61, 余额为: 9.67第17个人拿到红包数为:1.37, 余额为: 8.30第18个人拿到红包数为:0.67, 余额为: 7.63第19个人拿到红包数为:0.28, 余额为: 7.35第20个人拿到红包数为:0.96, 余额为: 6.39第21个人拿到红包数为:1.30, 余额为: 5.09第22个人拿到红包数为:1.08, 余额为: 4.01第23个人拿到红包数为:1.12, 余额为: 2.89第24个人拿到红包数为:0.75, 余额为: 2.14第25个人拿到红包数为:0.64, 余额为: 1.50第26个人拿到红包数为:0.37, 余额为: 1.13第27个人拿到红包数为:0.01, 余额为: 1.12第28个人拿到红包数为:0.26, 余额为: 0.86第29个人拿到红包数为:0.31, 余额为: 0.55第30个人拿到红包数为:0.55, 余额为: 0.00 python 2.py 0.01 10 20 20.01 10 20 2第1个人拿到红包数为:1.62, 余额为: 18.38第2个人拿到红包数为:18.38, 余额为: 0.00 python 2.py 0.01 10 20 30.01 10 20 3第1个人拿到红包数为:4.58, 余额为: 15.42第2个人拿到红包数为:11.22, 余额为: 4.20第3个人拿到红包数为:4.20, 余额为: 0.00
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