PHP func_num_args() function introduction and usage examples

func_num_args(): Returns the number of parameters passed in to the calling function, the type is integer.

This function can be used in conjunction with func_get_arg() and func_get_args() to allow user-defined functions to receive variable-length parameter lists.

Return value

Returns the number of parameters passed into the function defined by the current user.

Usage example:

function foo()
{
   $numargs = func_num_args();//返回这个函数所含的参数
   echo "Num fo argumets : $numargs <br>\n";
   $arr=func_get_args();//返回一个数组给$arr
   print_r($arr);//输出这个数组所有的参数
   echo "<hr>";
   for($i=0;$i<=$numargs;$i++)
   {
       echo $arr[$i]."<br>";
   }
}
foo(1,2,3,45,6);

The running results are as follows:

Num fo argumets : 5
Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 45 [4] => 6 )
--------------------------------------------------------------------------------
1
2
3
45
6

Example 2:

<?php
function foo() {
    include &#39;./fna.php&#39;;
}
foo(&#39;First arg&#39;, &#39;Second arg&#39;);
?>
fna.php
<?php
$num_args = func_num_args();
var_export($num_args);
?>

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