Home > Article > Backend Development > Detailed explanation of python3 set (set)
add(add elements)
name = set(['Tom','Lucy','Ben']) name.add('Juny')print(name)#输出:{'Lucy', 'Juny', 'Ben', 'Tom'}
clear(clear all elements)
name = set(['Tom','Lucy','Ben']) name.clear()print(name)#输出:set()
copy(copy set collection)
name = set(['Tom','Lucy','Ben']) new_name = name.copy()print(new_name)#输出:{'Tom', 'Lucy', 'Ben'}
difference(returns different elements in two or more sets and generates a new set)
A = set([2,3,4,5]) B = set([3,4]) C = set([2]) n = n1.difference(n2,n3) print(n) #输出:{5} #返回A集合里面,在B和C集合中没有的元素,并生成新的集合
difference_update(delete In the A set, the elements that exist in the B set)
A = set([2,3,4,5]) B = set([4,5]) A.difference_update(B) print(A) #输出:{2, 3}
discard(remove the element)
n = set([2,3,4]) n.discard(3)print(n)#输出:{2, 4}
intersection(take the intersection and generate a new set)
n1 = set([2,3,4,5]) n2 = set([4,5,6,7]) n = n1.intersection(n2)print(n)#输出:{4, 5}
intersection_update(Get the intersection and modify the original set)
n1 = set([2,3,4,5]) n2 = set([4,5,6,7]) n1.intersection_update(n2)print(n1)#输出:{4, 5}
isdisjoint(Judge the intersection, return False if it is, True if not)
n1 = set([2,3,4,5]) n2 = set([4,5,6,7])print(n1.isdisjoint(n2))#输出:False
issubset(Judge the subset)
A = set([2,3]) B = set([2,3,4,5])print(A.issubset(B))#输出:True#A是B的子集
issuperset(Judge the parent set)
A = set([2,3]) B = set([2,3,4,5])print(B.issuperset(A))# 输出:True#B是A的父集
pop(Randomly remove an element)
n = set([2,3,4,5]) n1 = n.pop()print(n,n1)# 输出:{3, 4, 5} 2
remove(Remove the specified element)
n = set([2,3,4,5]) n.remove(2)print(n)# 输出:{3, 4, 5}
symmetric_difference(Get the intersection , and generate a new set)
A = set([2,3,4,5]) B = set([4,5,6,7])print(A.symmetric_difference(B))# 输出:{2, 3, 6, 7}
symmetric_difference_update(take the intersection, change the original set)
A = set([2,3,4,5]) B = set([4,5,6,7]) A.symmetric_difference_update(B)print(A)# 输出:{2, 3, 6, 7}
union(take the union, and generate a new set)
A = set([2,3,4,5]) B = set([4,5,6,7])print(A.union(B))# 输出:{2, 3, 4, 5, 6, 7}
update(take the union and change the original set)
A = set([2,3,4,5]) B = set([4,5,6,7]) A.update(B)print(A)# 输出:{2, 3, 4, 5, 6, 7}
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