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Introduction to the method of replacing multiple characters in python

高洛峰
高洛峰Original
2017-03-23 17:45:184006browse

先给出结论:
 要替换的字符数量不多时,可以直接链式

replace()

方法进行替换,效率非常高;
 如果要替换的字符数量较多,则推荐在 for 循环中调用

replace()

进行替换。
可行的方法:
1. 链式replace()

string.replace().replace()


    1.x 在

for

循环中调用

replace()

「在要替换的字符较多时」
2. 使用string.maketrans
3. 先 re.compile 然后 re.sub
……

def a(text):
 chars = ""
 for c in chars:
 text = text.replace(c, "\\" + c)
def b(text):
 for ch in ['&','#']:
 if ch in text:
  text = text.replace(ch,"\\"+ch)
import re
def c(text):
 rx = re.compile('([])')
 text = rx.sub(r'\\\1', text)
RX = re.compile('([])')
def d(text):
 text = RX.sub(r'\\\1', text)
def mk_esc(esc_chars):
 return lambda s: ''.join(['\\' + c if c in esc_chars else c for c in s])
esc = mk_esc('')
def e(text):
 esc(text)
def f(text):
 text = text.replace('&', '\&').replace('#', '\#')
def g(text):
 replacements = {"&": "\&", "#": "\#"}
 text = "".join([replacements.get(c, c) for c in text])
def h(text):
 text = text.replace('&', r'\&')
 text = text.replace('#', r'\#')
def i(text):
 text = text.replace('&', r'\&').replace('#', r'\#')

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