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Introduction to the method of returning query results in dictionary form in Python Sqlite3

高洛峰
高洛峰Original
2017-03-21 11:49:082738browse

SQLite3 itself does not natively provide dictionary cursors like pymysql.

cursor = conn.cursor(pymysql.cursors.DictCursor)

But the corresponding implementation plan has been reserved in the official documents.

def dict_factory(cursor, row):  
    d = {}  
    for idx, col in enumerate(cursor.description):  
        d[col[0]] = row[idx]  
    return d

Use this function instead of the conn.raw_factory attribute.

def dict_factory(cursor, row):  
    d = {}  
    for idx, col in enumerate(cursor.description):  
        d[col[0]] = row[idx]  
    return d  con = sqlite3.connect(":memory:") #打开在内存里的数据库
con.row_factory = dict_factory
cur = con.cursor()
cur.execute("select 1 as a")
print cur.fetchone()["a"]


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