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HomeBackend DevelopmentPHP TutorialDetailed explanation of the application of php in app development

As a server-side development language, php plays the role of connecting the client and the database in app development. The client completes the operation of the database by calling the interface developed by php, and the user business is implemented in the php code The logical part. The client needs to pass some parameters to the server php. The format of these parameters is negotiated and formulated by the client developer and the server developer. The two follow the same set of standards so that the data passed between the two parties can be correctly parsed. In actual development, data in the json format is widely used for the interaction of client and server data. Almost every language supports the parsing of json data. It is convenient to use json_encode() and json_decode() in php. Yes, very convenient.

You need to pay attention to the following points when developing interfaces for apps in PHP:

1. It is recommended to use json for data transmission. Json has strong cross-platform properties. Most programming languages ​​support json parsing. JSON is gradually replacing XML and becoming the universal format for network data.

2. In order to ensure the security of the interface, an authentication system must be added to ensure that the request for the PHP interface is from a legal source. In addition, encryption technology can also be used for transmitted data. Chapter 20 of this book discusses API interface signatures and information encryption.

3. For online APIs, try to use error_reporting(0) to close the error prompt, or write the error prompt to the log to facilitate future troubleshooting. The purpose of this is, on the one hand, to protect the security of the interface and prevent the output of error messages that should not be printed. On the other hand, it is to ensure that the output data format is correct and to prevent the interface call exception that occurs when the output error message is incorrectly parsed by the client.

4. There is a certain difference between developing API and WEB. If the format returned by the interface is not standardized and is parsed by the client, it may cause the client to crash and crash. Therefore, before the interface is online Be sure to test thoroughly.

5. Try to ensure the performance of the code written in PHP. Mobile applications have higher requirements for response speed than web applications. Because of the huge difference in the performance of users’ mobile phones, after the mobile application obtains data from the server Data reorganization, page rendering, etc. will consume more time than web applications.

Json is selected as the data transmission format between the client and the server, and then the meaning of each field in json must be agreed upon. Generally, at least three fields are defined in json data, namely return status code, return Status description and data content. For example, a json data defined to return user information is as follows:

{"code":0,"msg":"success","data":{"name":"chenxiaolong","age": "22","gender":"male"}}

The code value is 0, indicating that the client's request to the interface is successful. The msg field indicates the status of the request, which corresponds to the return status code code. data In is the specific content that the client wants to get, which contains the user information returned by the server. In the data field, developers can define different field formats according to different interface needs.

The simple code example of this interface is as follows:

function getUserInfo() {

$uid = $_REQUEST[‘uid'];

$user = new User();

if($data = $user->findByUid($uid) != false) {

$this->output($data);

} else {

$this->output('',1,'invalid uid');

}

}

The client calls the getUserInfo interface and passes in the user's uid parameter, and PHP receives the parameter into the mysql database user table according to this uidQueryUser related information, where User is an encapsulated user tableModel, which provides the findByUid method to query user information based on the user uid. If the user information is queried, the user information will be output, otherwise an error will be returned. The information is given to the client. The error status code returned here is defined as 1, which means an illegal uid, that is, the data record corresponding to the uid is not found in the user table.

The interface uses a public output method, which is a specific implementation of outputting json data. The sample code is as follows:

function output(,$data='',$code=0,$msg='success') {

$out = array('code'=$code,'msg'=>$msg,'data'=>$data);

echo json_encode($out);

}

Note that echo output is used when returning data to the client insteadreturn.

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