Python checks whether the URL is accessible normally

Today, the project manager asked me a question, asking me that there are 2,000 URLs here to check whether they can be opened normally. In fact, I refused. I knew that because I had to write code, I happened to learn some Python. When I thought about it, python It was easy to handle, so I chose python and started thinking about it:

1. First, 2000 URLs. It can be placed in a txt text
2. Put the URLs in the content into the array one by one through python
3. Open a simulated browser and access it.
4. If the access is normal, the output will be normal, and if there is an error, the error will be output.

Just throw away the code simply and crudely. Because it involves privacy, the picture has been coded

import urllib.request 
import time 
 
opener = urllib.request.build_opener() 
opener.addheaders = [('User-agent', 'Mozilla/49.0.2')] 
#这个是你放网址的文件名，改过来就可以了 
file = open('test.txt') 
lines = file.readlines() 
aa=[] 
for line in lines: 
  temp=line.replace('\n','') 
  aa.append(temp) 
print(aa) 
 
print('开始检查：') 
for a in aa: 
  tempUrl = a 
  try : 
    opener.open(tempUrl) 
    print(tempUrl+'没问题') 
  except urllib.error.HTTPError: 
    print(tempUrl+'=访问页面出错') 
    time.sleep(2) 
  except urllib.error.URLError: 
    print(tempUrl+'=访问页面出错') 
    time.sleep(2) 
  time.sleep(0.1)

Rendering:

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