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Detailed explanation of the effect of the secondary linkage menu implemented by php mysql_php skills
- 不言Original
- 2018-05-21 11:18:234845browse
the example in this article describes the secondary linkage menu effect implemented by php mysql. share it with everyone for your reference, the details are as follows:
<!--php+mysql二级联动-->
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=gb2312" />
<title>生成学院专业级联下拉菜单测试 </title>
</head>
<body>
<? //
/***********************************************
** 功 能： php+mysql+javascript实现学院专业二级级联下拉框
** 数据库：数据库名（ dms）、数据表（ colleges、 majors）
** 表 colleges中字段： college_id（ id编号）、 name（学院名）
** 表 majors中的字段： major_id（ id编号）、 college_id（学院 id）、 name（学院名）
** version 1.0
** 作 者： wu yaowen
***********************************************/
//****************** 连接选择数据库 ***************
$link = mysql_connect("localhost", "root", "123456")
or die("could not connect : " . mysql_error());
mysql_select_db("dms") or die("could not select database");
//******************提取学院信息 ******************
$querycol = "select * from colleges order by college_id ";
mysql_query("set names 'gb2312'");
$result1 = mysql_query($querycol) or die("query failed : " . mysql_error());
$colleges = array();
while( $row1 = mysql_fetch_array($result1) )
{
$colleges[] = $row1;
}
//print_r ($forum_data);
mysql_free_result($result1);
//**************获取专业信息 **************
$querymaj = "select * from majors order by college_id desc";
mysql_query("set names 'gb2312'");
if( !($result2 = mysql_query($querymaj)) )
{
die('could not query t_city list');
}
$majors = array();
while( $row2 = mysql_fetch_array($result2) )
{
$majors[] = $row2;
}
mysql_free_result($result2);
?>
<!--************ javascript处理 college-onchange *************-->
<script language = "javascript">
var majorcount; // 存储专业记录条数
// form_majors[] 储存专业 major数据，如 {(1,1,电子商务 ),(4,1,计算机科学 ),(3,2,古典文学 )}
form_majors = new array();
<?php
$num2 = count($majors); // $num2 获取专业表中记录的个数
?>
majorcount = <?php echo $num2;?>;
<?
for($j=0;$j<$num2;$j++) // 从 0开始取出上面 majors[]中存储的专业数据填充数组
{
?>
form_majors[<?echo $j;?>] = new array("<?echo $majors[$j]['major_id'];?>","<?echo $majors[$j]['college_id'];?>","<?echo $majors[$j]['name'];?>");
<?php
}
?>
function changecollege(college_id)
{
document.stu_add_form.major.length = 0;
var id=id;
var j;
document.stu_add_form.major.options[0] = new option('==选择专业 ==',''); // label的 value为空 ' '
for (j=0;j < majorcount; j++) // 从 0开始判断
{
if (form_majors[j][1] == college_id) // if college_id等于选择的学院的 id
{
document.stu_add_form.major.options[document.stu_add_form.major.length] = new option(form_majors[j][2], form_majors[j][0]);
}
}
}
</script>
<!--********************页面表单 *************************-->
<form name="stu_add_form" method="post">
选择： <select name="college" onchange="changecollege(document.stu_add_form.college.options[document.stu_add_form.college.selectedindex].value)" size="1">
<option selected>==请选择学院 ==</option>
<?php
$num = count($colleges);
for($i=0;$i<$num;$i++)
{
?>
<option value="<?echo $colleges[$i]['college_id'];?>"><?echo $colleges[$i]['name'];?></option>
<?
}
?>
</select>
<select name="major">
<option selected value="">==选择专业 ==</option>
</select>
</form>
</body>
</html>sql statement:
-- -- 表的结构 `colleges` -- CREATE TABLE IF NOT EXISTS `colleges` ( `college_id` int(8) NOT NULL auto_increment COMMENT '学院编号自动增加', `name` varchar(40) NOT NULL COMMENT '学院名称', PRIMARY KEY (`college_id`), UNIQUE KEY `name` (`name`) ) ENGINE=InnoDB DEFAULT CHARSET=gb2312 AUTO_INCREMENT=7 ; -- -- 导出表中的数据 `colleges` -- INSERT INTO `colleges` (`college_id`, `name`) VALUES (4, '化学与化工学院'), (1, '计算机与信息科学学院'), (6, '美术学院'), (2, '文学院'), (5, '音乐学院'), (3, '政治与公共管理学院'); -- -- 表的结构 `majors` -- CREATE TABLE IF NOT EXISTS `majors` ( `major_id` int(8) NOT NULL auto_increment COMMENT '专业号，自动增加', `name` varchar(40) NOT NULL COMMENT '专业名', `college_id` int(8) default NULL COMMENT '所在学院', `counsellor_id` int(10) default NULL COMMENT '辅导员', PRIMARY KEY (`major_id`), UNIQUE KEY `college_id` (`college_id`,`counsellor_id`) ) ENGINE=InnoDB DEFAULT CHARSET=gb2312 AUTO_INCREMENT=8 ; -- -- 导出表中的数据 `majors` -- INSERT INTO `majors` (`major_id`, `name`, `college_id`, `counsellor_id`) VALUES (1, '电子商务', 1, 1), (2, '音乐视唱', 5, 1), (3, '古典文学', 2, 1), (4, '计算机科学', 1, NULL), (5, '自动化', 1, NULL), (6, '现代文学', 2, NULL), (7, '新闻写作', 2, NULL);
i hope this article will be helpful to everyone in php programming.
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