Java's multiple methods to make double retain two decimal places. Java retains two decimal places.

The three results of

mport java.text.DecimalFormat;  

DecimalFormat    df   = new DecimalFormat("######0.00");   

double d1 = 3.23456  
double d2 = 0.0;
double d3 = 2.0;
df.format(d1); 
df.format(d2); 
df.format(d3);

are:

3.23
0.00 
2.00

java retains two decimal places:

Method 1:

Rounding

double   f   =   111231.5585;  
BigDecimal   b   =   new   BigDecimal(f);  
double   f1   =   b.setScale(2,   BigDecimal.ROUND_HALF_UP).doubleValue();

retains two decimal places Decimal

Method 2:

java.text.DecimalFormat   df   =new   java.text.DecimalFormat("#.00");  
df.format(你要格式化的数字);

Example:

new java.text.DecimalFormat("#.00").format(3.1415926)

#.00 means two decimal places, #.0000 means four decimal places, and so on...

Method three:

double d = 3.1415926;
String result = String .format("%.2f");

%.2f %. Represents any number of digits before the decimal point 2 Represents two decimal places The result after the format is f Represents floating point type

Method four:

NumberFormat ddf1=NumberFormat.getNumberInstance() ;
void setMaximumFractionDigits(int digits)

digits The number of digits displayed
Sets the maximum number of digits displayed after the decimal point for the formatted object, and the last digit displayed is rounded

import java.text.* ; 
import java.math.* ; 
class TT 
{ 
public static void main(String args[]) 
{ double x=23.5455; 
NumberFormat ddf1=NumberFormat.getNumberInstance() ;

ddf1.setMaximumFractionDigits(2); 
String s= ddf1.format(x) ; 
System.out.print(s); 
} 
}

import java.text.*;
DecimalFormat df=new DecimalFormat(".##");
double d=1252.2563;
String st=df.format(d);
System.out.println(st);

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