Summary of methods for obtaining file extensions in java [regular and string interception]

The example in this article describes how to obtain the file extension in java. Share it with everyone for your reference, the details are as follows:

Problem description: There is a String type: String imageName = "zy.jpg"; How can I intercept the suffix name after ".".

Solution 1: Use regular expressions

package csdnTest;
import java.util.regex.*;
public class CSDNTest
{
  public static void main(String[] ss)
  {
    String s="abc.jpg";
    //String regex=".+?//.(.+)";这种写法也是可以的，但我认为没有后面的精确
    String regex=".+?//.([a-zA-z]+)";
    Pattern pt=Pattern.compile(regex);
    Matcher mt=pt.matcher(s);
    if(mt.find())
    {
      System.out.println(mt.group(1));
    }
  }
}

Solution 2:

System.out.println(imageName.substring(imageName.lastIndexOf('.')+1));

or

String FileType=imageName.substring(imageName.lastIndexOf('.')+1,imageName.length());

I hope this article will help everyone’s java program Design helps.

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