Python regular expression method to intercept pairs of brackets

The example of this article describes the method of intercepting pairs of brackets using Python regular expressions. Share it with everyone for your reference, as follows:

strs = '1(2(3(4(5(67)6)7)8)9)0'
reg1 = re.compile('([()])∗') #一对括号
reg2 = re.compile('([()]|\([()]∗)*\)') #两对括号
reg3 = re.compile('([()]|\([()]∗|([()]|\([()]∗)*\))*\)') #三层

Function

#匹配成对括号正则表达式
def getReg(self, count, bracket = '()'):
    leftBracket = bracket[0]
    rightBracket = bracket[1]
    count -= 1
    regBasic = leftBracket + '(?:[^' + leftBracket + rightBracket + '])*' + rightBracket
    if count < 0:
      regBasic = ''
    if count > 0:
      for i in xrange(count):
        tempNum = regBasic.rfind('*') - 1
        regBasic = regBasic[:tempNum] + "|" + regBasic + regBasic[tempNum:]
    return regBasic

I hope this article will be helpful to everyone in Python programming.

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