A judgment function is needed to return whether the time is legal or not, PHP

1. You need to write a function isValidDate($date), the conditions are as follows:

<code>function isValidDate($date)
{
    //1. $date 是本周时 +  time()要在$date前一天的18：00之前 = true
    
    //2. $date 为下周时 +  time()要在本周四下午六点后  = true
    
    //3. 其余返回false.    (注：一周从周一开始)
    
    $orderTime = strtotime($date);
    $now = time();
    if(date('W',$orderTime) == date('W',$now) && (strtotime($date,$now) - $now) > 86400/4)   //预订前一天的18:00,截止预订
    {    
        return true;
    }
    if(date('W',$orderTime) == date('W',$now) + 1 && $now > strtotime('saturday 18:05 -2 day',$now)) //预订第二周,周四下午六点及之后
    {
        return true;
    }
        return false;

}</code>

Among them, when I wrote the second condition, I found that there seemed to be a problem with the time covered by the condition. I would like to see your opinions.

Reply content:

1. You need to write a function isValidDate($date), the conditions are as follows:

<code>function isValidDate($date)
{
    //1. $date 是本周时 +  time()要在$date前一天的18：00之前 = true
    
    //2. $date 为下周时 +  time()要在本周四下午六点后  = true
    
    //3. 其余返回false.    (注：一周从周一开始)
    
    $orderTime = strtotime($date);
    $now = time();
    if(date('W',$orderTime) == date('W',$now) && (strtotime($date,$now) - $now) > 86400/4)   //预订前一天的18:00,截止预订
    {    
        return true;
    }
    if(date('W',$orderTime) == date('W',$now) + 1 && $now > strtotime('saturday 18:05 -2 day',$now)) //预订第二周,周四下午六点及之后
    {
        return true;
    }
        return false;

}</code>

Among them, when I wrote the second condition, I found that there seemed to be a problem with the time covered by the condition. I would like to see your opinions.

Why do you feel like you are forcing yourself to do interview questions for others? Since I can list 123 in an orderly manner, implementation should not be a problem. . .

Install Carbon

use Carbon\Carbon;

/**
 * 校验日期
 * @param  string  $date 日期
 * @return boolean       
 */
function isValidDate($date)
{
    // $date 是本周时 +  time()要在$date前一天的18：00之前 = true
    if (Carbon::parse($date)->format('W') == Carbon::now()->format('W') &&
        time() < Carbon::parse($date)->subDay(1)->hour(18)->minute(0)->timestamp
    ) {
        return true;
    }
    // $date 为下周时 +  time()要在本周四下午六点后  = true
    elseif (
        Carbon::parse($date)->format('W') == Carbon::now()->addWeek(1)->format('W') &&
        time() > Carbon::now()->startOfDay()->addDay(3)->hour(18)->minute(0)->timestamp
    ) {
        return true;
    }

    return false;
}

Simply change the if statement in the title of the question return

<code>function isValidDate($date)
{
    //1. $date 是本周时 +  time()要在$date前一天的18：00之前 = true
    
    //2. $date 为下周时 +  time()要在本周四下午六点后  = true
    
    //3. 其余返回false.    (注：一周从周一开始)
    
    $orderTime = strtotime($date);
    $now = time();
    if(date('W',$orderTime) === date('W',$now)) // 当前周
    {    
        // time()要在$date前一天的18：00之前 = true
        return $now  strtotime(date('Y-m-d 18:00:00',strtotime( '+'. 4-date('w') .' days' )));
    }
    return false;

}</code>