The PHP web page generates a QR code, and the Android client scans the code to log in.
- 大家讲道理Original
- 2016-11-08 11:41:551443browse
使用了Github上具有扫码功能的ZXing开源库，使用了通过随机数生成二维码图片网络API，整个过程经过三步：
1.PHP网页生成二维码，相应随机数存储到数据库中；
2.Android客户端扫码，携带username保存至随机数对应的位置；
3.每隔一段时间，PHP通过Ajax轮询数据库，判断是否为空，不为空则跳转网页。
<html>
<head>
<title>qrlogin</title>
<meta charset="UTF-8"/>
</head>
<body>
<?php
/**
* @author Cenquanyu
* @version 2016年5月12日
*
*/
require 'mysql_connect.php';
$randnumber = "";
for($i=0;$i<8;$i++){
$randnumber.=rand(0,9);
}
//将生成的随机数保存至数据库
mysql_query("insert into login_data (randnumber) values ('$randnumber')")
?>
<img src="http://qr.liantu.com/api.php?text=<?php echo $randnumber;? alt="The PHP web page generates a QR code, and the Android client scans the code to log in." >" width="300px"/>
<input hidden="hidden" type="text" name="randnumber" id="randnumber"value="<?php echo $randnumber;?>"/>
</body>
<script>
xmlHttpRequest.onreadystatechange = function(){
if(xmlHttpRequest.status == 200 && xmlHttpRequest.readyState ==4){
result = xmlHttp.responseText;
if(result==true){//username不为空则跳转页面
window.location.href='welcome.php';
}
}
}
}
function polling(){
//执行轮询操作
var xmlHttpRequest;
if(window.XMLHttpRequest){
xmlHttpRequest = new XMLHttpRequest();
}
else{
xmlHttpRequest = new ActiveXObject("Microsoft.XMLHTTP");
}
randnumber = document.getElementById('randnumber').value;
xmlHttpRequest.open("GET","polling.php?randnumber="+ randnumber,true);
xmlHttpRequest.send();
}
setInterval("polling()",1000);
</script>
</html>Statement：
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