Home >Backend Development >Python Tutorial >A relatively memory-saving sparse matrix Python storage solution
Recommendation systems often need to process data like user_id, item_id, rating, which are actually sparse matrices in mathematics. Scipy provides the sparse module to solve this problem, but scipy.sparse has many problems that are not suitable for use: 1. It cannot It supports fast slicing of data[i, ...], data[..., j], and data[i, j] at the same time; 2. Because the data is stored in memory, it cannot well support massive data processing.
To support fast slicing of data[i, ...], data[..., j], the data of i or j needs to be stored centrally; at the same time, in order to save massive data, part of the data also needs to be placed in On the hard disk, use memory as a buffer. The solution here is relatively simple. Use a Dict-like thing to store data. For a certain i (such as 9527), its data is stored in dict['i9527']. Similarly, for a certain j (such as 3306) , all its data is stored in dict['j3306']. When you need to take out data[9527, ...], just take out dict['i9527']. dict['i9527'] is originally a dict object , stores the value corresponding to a certain j. In order to save memory space, we store this dict in the form of a binary string and directly enter the code:
''' Sparse Matrix ''' import struct import numpy as np import bsddb from cStringIO import StringIO class DictMatrix(): def __init__(self, container = {}, dft = 0.0): self._data = container self._dft = dft self._nums = 0 def __setitem__(self, index, value): try: i, j = index except: raise IndexError('invalid index') ik = ('i%d' % i) # 为了节省内存,我们把j, value打包成字二进制字符串 ib = struct.pack('if', j, value) jk = ('j%d' % j) jb = struct.pack('if', i, value) try: self._data[ik] += ib except: self._data[ik] = ib try: self._data[jk] += jb except: self._data[jk] = jb self._nums += 1 def __getitem__(self, index): try: i, j = index except: raise IndexError('invalid index') if (isinstance(i, int)): ik = ('i%d' % i) if not self._data.has_key(ik): return self._dft ret = dict(np.fromstring(self._data[ik], dtype = 'i4,f4')) if (isinstance(j, int)): return ret.get(j, self._dft) if (isinstance(j, int)): jk = ('j%d' % j) if not self._data.has_key(jk): return self._dft ret = dict(np.fromstring(self._data[jk], dtype = 'i4,f4')) return ret def __len__(self): return self._nums def __iter__(self): pass ''' 从文件中生成matrix 考虑到dbm读写的性能不如内存,我们做了一些缓存,每1000W次批量写入一次 考虑到字符串拼接性能不太好,我们直接用StringIO来做拼接 ''' def from_file(self, fp, sep = 't'): cnt = 0 cache = {} for l in fp: if 10000000 == cnt: self._flush(cache) cnt = 0 cache = {} i, j, v = [float(i) for i in l.split(sep)] ik = ('i%d' % i) ib = struct.pack('if', j, v) jk = ('j%d' % j) jb = struct.pack('if', i, v) try: cache[ik].write(ib) except: cache[ik] = StringIO() cache[ik].write(ib) try: cache[jk].write(jb) except: cache[jk] = StringIO() cache[jk].write(jb) cnt += 1 self._nums += 1 self._flush(cache) return self._nums def _flush(self, cache): for k,v in cache.items(): v.seek(0) s = v.read() try: self._data[k] += s except: self._data[k] = s if __name__ == '__main__': db = bsddb.btopen(None, cachesize = 268435456) data = DictMatrix(db) data.from_file(open('/path/to/log.txt', 'r'), ',')
Test 4500W rating data (integer, integer, floating point format ), a 922MB text file is imported. If the memory dict is used to store it, the construction is completed in 12 minutes, consuming 1.2G of memory. Using the bdb storage in the sample code, the construction is completed in 20 minutes, occupying about 300~400MB of memory, which is not much larger than cachesize. Data reading Take the test:
import timeit timeit.Timer('foo = __main__.data[9527, ...]', 'import __main__').timeit(number = 1000)
consumes 1.4788 seconds, and it takes about 1.5ms to read a piece of data.
Another benefit of using Dict class to store data is that you can use memory Dict or any other form of DBM, or even the legendary Tokyo Cabinet…