javascript - ajax value transfer always passes the last value of the obtained data

ajax value transfer can only transfer the last value of the data, or it is a loop. The loop problem is solved and only the last value can be passed.

z is the post ID set by me

Reply content:

ajax value transfer can only transfer the last value of the data, or it is a loop. The loop problem is solved and only the last value can be passed.

z is the post ID set by me

When the click callback is executed, the loop has finished running, z must be allTopic.length+1, you can use something like

<code>for(var i=0;i<length;i++){
  $('test').click(function(i){
    return function(){
      $.ajax()//use i
    }
  }(i))
}
</code>

Solution

Why don’t you just concatenate the ID you want to pass into a string or process it into an array, and pass the value in one go? It consumes too much to request the server every time!