php-Is my understanding correct? The reason why $b outputs 1 is because $a defaults to 0?

  php

• <?phpfunction test (&$b){    $b++;    echo $b.&#39;&#39;;
  }test($a);$a=100;echo $a;

Reply content:

This code has been changed to better understand the changes in $a:

<?php
function test (&$b){
$b++;
echo $b.&#39;
&#39;;
}
test($a);
echo $a;
$a=100;
echo $a;

Yes, php will initialize a default value for unassigned code. For integers, This value is 0

The initialization value is the same as java.
What should I pay attention to when studying? I think the most important thing is to apply what you have learned, practice more, and write some code that has practical significance. Don’t write too much helloworld-level code, let alone go overboard and create some weird test programs, and pay more attention to real-world problems. .

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