The android client accesses the server it created and returns JSON data for parsing and learning.

Recently I am looking for use cases about client access server development. I always visit other people’s websites and cannot modify the data inside. I don’t know how to achieve it. I applied for a free server website online and uploaded a php file. , now you can access the information on the server through urlStr===http://1.hellowes.sinaapp.com/, and the server will return a data. Since I don’t know PHP at all, what is returned on the server is not the real data. JSON data, so I had to combine the client string into a JSON statement and parse it through JSONObject.

The implementation code is posted below, and finally I can get the information from the server

public JSONObject getweb(String urlStr) throws Exception{

StringBuffer sb = new StringBuffer();
try {
URL url = new URL(urlStr);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setConnectTime out (5000);
conn.setDoInput(true);
conn.setDoOutput(true);
if(conn.getResponseCode() == 200){
InputStream is = conn.getInputStream();
int len ​​= 0;
byte[] buf = new byte[1024];
while((len = is.read(buf)) != -1){
sb.append(new String(buf, 0, len, "UTF-8") ; .printStackTrace();
throw new Exception("Failed to access network 11");
}
System.out.println("---------"+sb.toString());
String htmlStr = sb.toString();
htmlStr = htmlStr.replaceAll(""", "'");

htmlStr = "{'singer':"+htmlStr+"}";

System.out.println("htmlStr=== ="+htmlStr);
JSONObject jsonObj = null;
try {
jsonObj = new JSONObject(htmlStr).getJSONObject("singer");
System.out.println("jsonObj===="+jsonObj);
} catch (JSONException e1) {
// TODO Auto-generated catch block

e1.printStackTrace();
}

return jsonObj;

}

The above introduces how the android client accesses the server established by itself and returns JSON data for parsing and learning, including the content. I hope it will be helpful to friends who are interested in PHP tutorials.