本文实例讲述了php出现web系统多域名登录失败的解决方法,分享给大家供大家参考。具体分析如下:
下面只是简单的逻辑结构,对于正式的系统需要做具体的处理。
这里需要注意的是:加解密一定需要做安全验证。但是这个方法也不够完美,两个站点必须有相同一级域名;另外这种完全基于cookie的方式,安全性不够高
function login() { $info = callloginserver(); //访问登录服务器 if(!empty($info)) //登录成功了 } //用户没有登录,则在本系统中登录并调用登录服务器接口 function login() //正常的登录 { .......//验证用户的合法性 $_session['uid'] = $user_id; setcookie('sign', encrypt($pass9), '', '/', 'the.com'); }
先检查用户是否在登录系统中登录
funtion sign() { $sign = $_cookie['sign']; if(!empty($sign)) { $sign = decrypt($sign); ..........///登录成功 } }
用户没有登录,则在本系统中登录并调用登录服务器接口
function loging() //本系统登录 { .....//登录成功 callseverlogin();//通知用户登录 }
所有的站点共享一个登录系统;当用户在其中的一个站点登录成功时, 该系统调用其他站点的登录接口,完成用户在其他站点的登录,同时设置相应的登录信息;或者在用户登录时,只在该系统保存用户登录信息,当用户在其他站点登录时,必须请求该系统接口,获取用户是否登录的信息。前一种方式的缺点是:不管用户有没有使用其他站点,那些站点都需要保存用户状态;后一种方式就把所有的压力都转移到登录系统上面来。而如果要实现用户退出的统一操作,就需要站点调用登录系统的退出接口,然后登录系统接口调用其他站点的退出接口;或者设置一个标记,如果这个标记不存在则标示用户退出,此时只要把该标示清空即可,其他站点发现该标示不存在就知道用户已经退出系统。
这种处理方式需要在登录系统和个站点之间规定登录接口,和注销接口。通过这些接口,各站点可以很方便的处理用户登录或退出。
希望本文所述对大家的PHP程序设计有所帮助。

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