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Instructions for using the php in_array function and instructions for what you need to pay attention to in_array_PHP Tutorial
- WBOYOriginal
- 2016-07-21 15:39:20828browse
in_array
(PHP 4, PHP 5)
in_array — Check if a value exists in the array
Description
Copy codeThe code is as follows:
bool in_array ( mixed $needle , array $haystack [, bool $strict ] )
Search needle in haystack, if found, return TRUE, otherwise return FALSE.
If the value of the third parameter strict is TRUE, the in_array() function will also check whether the type of needle is the same as that in haystack.
Note: If needle is a string, the comparison is case-sensitive.
Note: Prior to PHP version 4.2.0, needle was not allowed to be an array.
Example #1 in_array() >$os = array("Mac", "NT", "Irix", "Linux");
if (in_array("Irix", $os)) {
echo "Got Irix"; } if (in_array("mac", $os)) { echo "Got mac"; }
?> The second condition fails because in_array() is case-sensitive, so the above program is displayed as:
Got Irix
Example #2 in_array() strict type checking example
The code is as follows:
$a = array('1.10', 12.4, 1.13);
if (in_array('12.4', $a, true)) { echo "'12.4' found with strict checkn"; } if (in_array (1.13, $a, true)) { echo "1.13 found with strict checkn";
} ?>
The above example will output:
1.13 found with strict check
Example #3 Use array as needle in_array()
Copy code
The code is as follows:
$a = array(array('p', 'h'), array('p', 'r'), 'o') ;
The above example will output:
1.13 found with strict check
Example #3 Use array as needle in_array()
Copy code
The code is as follows:
$a = array(array('p', 'h'), array('p', 'r'), 'o') ;
if (in_array(array('p', 'h'), $a)) { echo "'ph' was foundn"; } if (in_array( array('f', 'i'), $a)) { echo "'fi' was foundn";
} if (in_array('o', $a)) {
echo "'o' was foundn";
}
?>
The above example will output:
'ph' was found
'o ' was found
Things to note:
If:
First declare an array as:
$arr = array(
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truehttp: //www.bkjia.com/PHPjc/321552.html
echo "'o' was foundn";
}
?>
The above example will output:
'ph' was found
'o ' was found
Things to note:
If:
First declare an array as:
$arr = array(
*
);
Puzzling!
{Weak language}
Solution:
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