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Function code for randomly displaying pictures in php_PHP tutorial

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WBOYOriginal
2016-07-21 15:28:04860browse

For example, the display window of the blog

Copy the code The code is as follows:

/**********************************************
* Filename : img.php
* Author : freemouse
* web : www.cnphp.info
* email :freemouse1981@gmail.com
* Date : 2010/12/27
* Usage:
*
*
********************************************** */
if($_GET['folder']){
$folder=$_GET['folder'];
}else{
$folder='/images/';
}
//The location where image files are stored
$path = $_SERVER['DOCUMENT_ROOT']."/".$folder;
$files=array();
if ($handle =opendir("$path")) {
while(false !== ($file = readdir($handle))) {
if ($file != "." && $file != ". .") {
if(substr($file,-3)=='gif' || substr($file,-3)=='jpg') $files[count($files)] = $file ;
}
}
}
closedir($handle);

$random=rand(0,count($files)-1);
if(substr ($files[$random],-3)=='gif') header("Content-type: image/gif");
elseif(substr($files[$random],-3)==' jpg') header("Content-type: image/jpeg");
readfile("$path/$files[$random]");
?>

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/323656.htmlTechArticleFor example, the blog display window copy code is as follows: ?php /************* *********************************** * Filename : img.php * Author : freemouse * web : www. cnphp.info * email :fr...
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