Adding php arrays array("a")+array("b") results in array("a")_PHP Tutorial

I saw a question online:

The result of array("a")+array("b") is___

A.array("a","b")
B.array("b","a")
C.array("b")
D.array("a ")

Answer: D

When adding two arrays in PHP, why does the result remain unchanged?

Because, they are equivalent to array("0″=>"a")+array("0″=>"b"), their key names are the same, the former cannot be overwritten by the latter, if array("0″=>"a")+array("0″=>"b", "1″=>"c"), then the result is equal to array("0″=>"a" ,"1″=>"c")

What will happen if there are the same key names in the same array?

Look at a piece of code from the official PHP manual:

Copy code The code is as follows:

$switching = array( 10, // key = 0
5 5 => 6,
3 => 7,
'a' => 4,
11, // key = 6 (maxim um of integer-indices was 5)
                                                                                                                             // key = 8 (integer!)
                                                                                   );

It can be seen that if there are the same key names in the same array, the value of the previous key name will be overwritten (overwritten).

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www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/325972.htmlTechArticleI saw a question on the Internet: The result of array("a")+array("b") is_ __ A.array("a","b") B.array("b","a") C.array("b") D.array("a") Answer: D Add two arrays in php , why the result is still not...