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HomeBackend DevelopmentPHP TutorialHow does PHP return data in json format to jquery_PHP tutorial
How does PHP return data in json format to jquery_PHP tutorialJul 13, 2016 pm 05:15 PM
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Json format data is data that we have always used in application development. For example, when dealing with jquery or api, json data will be used. So how does PHP return json format data to jquery? The following Let me introduce it to all my classmates.

To operate json data in jquery, we directly use $.parseJSON(returnString)

Example

 代码如下 复制代码
$(function(){
     $('#send').click(function() {
          $.getJSON('test.js', function(data) {
              $('#resText').empty();
   var html = '';
   $.each( data  , function(commentIndex, comment) {
    html += '
' + comment['username'] + ':

' + comment['content'] + '

';
   })
  $('#resText').html(html);
         })
    })
})

All you need to do is store the data as a properly formatted .json or .js file. The following is the json format data transmitted in the example

The code is as follows Copy code
 代码如下 复制代码


[
  {
    "username": "张三",
    "content": "沙发."
  },
  {
    "username": "李四",
    "content": "板凳."
  },
  {
    "username": "王五",
    "content": "地板."
  }
]

[

{

"username": "张三",
"content": "Sofa."

},

{

"username": "李思",

"content": "Bench." }, {

"username": "王五",

"content": "Floor."

}

]

 代码如下 复制代码

header('Content-type: text/json');

$fruits = array (
    "fruits"  => array("a" => "orange", "b" => "banana", "c" => "apple"),
    "numbers" => array(1, 2, 3, 4, 5, 6),
    "holes"   => array("first", 5 => "second", "third")
);
echo json_encode($fruits);
?>

The json data mentioned above is fixed. How do we use php to return the json data PHP output JSON format method Add to the page header('Content-type: text/json'); This header is to tell the output type of this file is json. The most common form we see is verification code - PHP outputs verification pictures. Sometimes PHP can output css files, js files, etc. to do some interesting things. Okay, let’s test it
The code is as follows Copy code
header('Content-type: text/json'); $fruits = array ( "fruits" => array("a" => "orange", "b" => "banana", "c" => "apple"), "numbers" => array(1, 2, 3, 4, 5, 6), "holes" => array("first", 5 => "second", "third") ); echo json_encode($fruits); ?>

Example

The data read from the database generates json format

The code is as follows
 代码如下 复制代码




第一php网提供的教程--将数据库读取的数据生成json格式





<br>
<h1 id="请注意两种方法生成的对象数组在结构上的区别">请注意两种方法生成的对象数组在结构上的区别</h1><br>
<?php <br />
echo '<h1 id="法一">法一</h1>';<br>
//假设以下数组是根据我们从数据库读取的数据生成的<br>
$jarr=array('total'=>239,'row'=>array(<br>
           array('code'=>'001','name'=>'中国','addr'=>'Address 11','col4'=>'col4 data'),<br>
           array('code'=>'002','name'=>'Name 2','addr'=>'Address 12','col4'=>'col4 data'),<br>
                                     )<br>
           );<br>
//法一:<br>
$jobj=new stdclass();//实例化stdclass,这是php内置的空类,可以用来传递数据,由于json_decode后的数据是以对象数组的形式存放的,<br>
//所以我们生成的时候也要把数据存储在对象中<br>
foreach($jarr as $key=>$value){<br>
$jobj->$key=$value;<br>
}<br>
print_r($jobj);//打印传递属性后的对象<br>
echo '使用$jobj->row[0]['code']输出数组元素:'.$jobj->row[0]['code'].'<br>';<br>
echo '编码后的json字符串:'.json_encode($jobj).'<br>';//打印编码后的json字符串
<p>//法二:<br>
echo '</p><hr>';<br>
echo '<h1 id="法二">法二</h1>';<br>
echo '编码后的json字符串:';<br>
echo $str=json_encode($jarr);//将数组进行json编码<br>
echo '<br>';<br>
$arr=json_decode($str);//再进行json解码<br>
print_r($arr);//打印解码后的数组,数据存储在对象数组中<br>
echo '使用$arr->row[0]->code输出数组元素:'.$arr->row[0]->code;
<p>?></p>
<p><br>
<br>
</p>
Copy code


Tutorial provided by the first php website - Generate json format from data read from the database





<br>
<h1 id="Please-note-the-structural-difference-between-the-object-arrays-generated-by-the-two-methods">Please note the structural difference between the object arrays generated by the two methods</h1><br>
<?php <br />
echo '<h1 id="法一">法一</h1>';<br>
//Assume that the following array is generated based on the data we read from the database<br>
$jarr=array('total'=>239,'row'=>array(<br>
              array('code'=>'001','name'=>'China','addr'=>'Address 11','col4'=>'col4 data'),<br>
              array('code'=>'002','name'=>'Name 2','addr'=>'Address 12','col4'=>'col4 data'),<br>
)<br>
);<br>
//Method 1:<br>
$jobj=new stdclass();//Instantiate stdclass, which is an empty class built into PHP and can be used to transfer data. Since the data after json_decode is stored in the form of an object array,<br>
//So we also need to store the data in the object when generating<br>
foreach($jarr as $key=>$value){<br>
$jobj->$key=$value;<br>
}<br>
print_r($jobj);//Print the object after passing the attributes<br>
echo 'Use $jobj->row[0]['code'] to output array elements:'.$jobj->row[0]['code'].'<br>';<br>
echo 'Encoded json string:'.json_encode($jobj).'<br>';//Print the encoded json string
<p align="left">//Method 2:<br>
echo '</p><hr>';<br>
echo '<h1 id="Method">Method 2</h1>';<br>
echo 'Encoded json string:';<br>
echo $str=json_encode($jarr);//Encode the array into json<br>
echo '<br>';<br>
$arr=json_decode($str);//Decode json again<br>
print_r($arr);//Print the decoded array, the data is stored in the object array<br>
echo 'Use $arr->row[0]->code to output array elements:'.$arr->row[0]->code;<div style="display:none;">
<span id="url" itemprop="url">?></span>
<span id="indexUrl" itemprop="indexUrl"><br>
<br>
</span>
<span id="isOriginal" itemprop="isOriginal">
</span>
<span id="isBasedOnUrl" itemprop="isBasedOnUrl"></span>
<span id="genre" itemprop="genre">
</span><span id="description" itemprop="description">
</span>
</div>http://www.bkjia.com/PHPjc/628765.html<div class="art_confoot">www.bkjia.com</div>truehttp: //www.bkjia.com/PHPjc/628765.htmlTechArticleThe data in json format is the data we have always used in application development, such as when dealing with jquery or JSON data will be used when dealing with APIs, so how does PHP return json format data to...
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