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$time = strtotime("2011-03-31");
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> php -r”echo date(‘Ymd000000′,strtotime (‘-1 month’, strtotime (’201307310000′)));”
20130701000000#
> php -r”echo date(‘Ymd000000′,strtotime (‘-1 month’, strtotime (’201308010000′)));”
20130701000000#
After searching, the following method is more accurate
| The code is as follows
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| 代码如下 |
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function last_month_day($time){
$strtime=mktime(date('h',$time),date('i',$time),date('s',$time),date('m',$time)-1,date('d',$time),date('Y',$time));
echo date('Y-m-d',$strtime);
}
last_month_day(strtotime("2012-03-31"));
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$time = strtotime("2011-03-31");
Function mktime, which can get the timestamp of the date:
| 代码如下 |
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/**
* 计算上一个月的今天，如果上个月没有今天，则返回上一个月的最后一天
* @param type $time
* @return type
*/
function last_month_today($time){
$last_month_time = mktime(date("G", $time), date("i", $time),
date("s", $time), date("n", $time), 0, date("Y", $time));
$last_month_t = date("t", $last_month_time);
if ($last_month_t < date("j", $time)) {
return date("Y-m-t H:i:s", $last_month_time);
}
return date(date("Y-m", $last_month_time) . "-d", $time);
}
echo last_month_today($time);
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int mktime ([ int $hour [, int $minute [, int $second [, int $month [, int $day [, int $year [, int $is_dst ]]]]]] ) |
Returns a Unix timestamp based on the given arguments. A timestamp is a long integer containing the number of seconds since the Unix epoch (January 1 1970 00:00:00 GMT) to a given time.
Parameters can be omitted from right to left. Any omitted parameters will be set to the current value of the local date and time.
So it can be calculated
| The code is as follows
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function last_month_day($time){
$strtime=mktime(date('h',$time),date('i',$time),date('s',$time),date('m',$time)-1,date(' d',$time),date('Y',$time));
echo date('Y-m-d',$strtime);
}
last_month_day(strtotime("2012-03-31"));
The output result is 2012-03-02; logically it should be the output 2012-02-31???? Idiot, is there a 31st in February? No, is there a 30th, no? Is there a 29th?... This. .Can have…
PHP handles this situation for us, and it will give us a few more days to calculate next month.
The last day of February 2012 is 2012-02-29, so the 31st is two days longer than the 29th, so PHP will add it up to the next month for processing, which is 2012-03-02.
I almost forgot... So how do we calculate the day of the week? No need to calculate it... PHP has prepared it for us.
date(‘w’,$strtime); The output is the day of the week. It is the day of the week.
Example
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/**
* Calculate today's day of the previous month. If there is no today in the previous month, return the last day of the previous month
* @param type $time
* @return type
*/
function last_month_today($time){
$last_month_time = mktime(date("G", $time), date("i", $time),
date("s", $time), date("n", $time), 0, date("Y", $time));
$last_month_t = date("t", $last_month_time);
if ($last_month_t < date("j", $time)) {
return date("Y-m-t H:i:s", $last_month_time);
}
return date(date("Y-m", $last_month_time) . "-d", $time);
}
echo last_month_today($time);
http://www.bkjia.com/PHPjc/633186.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/633186.htmlTechArticleToday the editor will introduce to you a solution to the problem of calculating today's date in the previous month with PHP strtotime. If you encounter If there is any problem in calculating the previous month today, please do not enter the reference. PHP, last month...
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