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PHP sends post request function sharing_PHP tutorial

WBOY
WBOYOriginal
2016-07-13 10:37:11701browse

Copy code The code is as follows:

function do_post_request($url, $data, $optional_headers = null)
{
$params = array('http' => array(
'method' => 'POST',
'content' => $data
));
if ($optional_headers !== null) {
$params['http']['header'] = $optional_headers;
}
$ctx = stream_context_create($params);
$fp = @fopen($url, 'rb', false, $ctx);
if (!$fp) {
throw new Exception("Problem with $url, $php_errormsg");
}
$response = @stream_get_contents($fp);
if ($response === false) {
throw new Exception("Problem reading data from $url, $php_errormsg");
}
return $response;
}


usage is as follows:

Copy code The code is as follows:

//json string
$ data = "{...}";
//Convert to array
$data=json_decode($data,true);
$postdata = http_build_query($data);
do_post_request(" http://localhost",$postdata);

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/736791.htmlTechArticleCopy the code The code is as follows: function do_post_request($url, $data, $optional_headers = null) { $params = array ('http' = array( 'method' = 'POST', 'content' = $data )); if ($optional_...
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