Implementing function overloading in PHP_PHP tutorial

Originally php?name=PHP">PHP does not support function overloading!

As a weakly typed language, php itself cannot directly implement overloading like strongly typed languages ​​such as java and c++. However, overloading can be achieved indirectly through some methods.

1. You can use the two functions func_get_args() and func_num_args() to implement function overloading!!

PHP code:

    <span>function</span><span> rewrite() {   
            </span><span>$args</span> = <span>func_get_args</span><span>();   
            </span><span>if</span>(<span>func_num_args</span>() == 1<span>) {   
                    func1(</span><span>$args</span>[0<span>]);   
            } </span><span>else</span> <span>if</span>(<span>func_num_args</span>() == 2<span>) {   
                    func2(</span><span>$args</span>[0], <span>$args</span>[1<span>]);   
            }   
    }   
      
    </span><span>function</span> func1(<span>$arg</span><span>) {   
            </span><span>echo</span> <span>$arg</span><span>;   
    }   
      
    </span><span>function</span> func2(<span>$arg1</span>, <span>$arg2</span><span>) {   
            </span><span>echo</span> <span>$arg1</span>, ' ', <span>$arg2</span><span>;   
    }   
      
    rewrite(</span>'PHP'); <span>//</span><span>调用func1   </span>
    rewrite('PHP','China'); <span>//</span><span>调用func2   </span>

2. Use the default value to get the results you want based on the input:

 <span>function</span> test(<span>$name</span>="小李",<span>$age</span>="23"<span>){  
        </span><span>echo</span> <span>$name</span>."  ".<span>$age</span><span>;  
        }  
  
    test();  
    </span><span>echo</span> "<br/>"<span>;  
    test(</span>"a"<span>);  
    </span><span>echo</span> "<br/>"<span>;  
    test(</span>"a","b"); 

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