How to accurately calculate Easter date in php, php Easter date_PHP tutorial

How to accurately calculate the Easter date in php, php Easter date

The example in this article describes the method of accurately calculating the Easter date in php. Share it with everyone for your reference. The details are as follows:

<&#63;PHP
function isLeapYear( $nYEAR ) {
 if((($nYEAR % 4 == 0) AND !($nYEAR % 100 == 0)) AND ($nYEAR % 400 != 0))
 {
  return TRUE;
 } else {
  return FALSE;
 }
}
function div( $a, $b ){
 return( $a - ( $a % $b )) / $b;
}
function easterSunday( $nYEAR ) {
 // The function is able to calculate the date 
 //of eastersunday back to the year 325,
 // but mktime() starts at 1970-01-01!
 if ( $nYEAR < 1970 ) {
  $dtEasterSunday = mktime( 1,1,1,1,1,1970 );
 } else {
  $nGZ = ( $nYEAR % 19 ) + 1;
  $nJHD = div( $nYEAR, 100 ) + 1;
  $nKSJ = div( 3 * $nJHD, 4 ) - 12;
  $nKORR = div( 8 * $nJHD + 5, 25 ) - 5;
  $nSO = div( 5 * $nYEAR, 4 ) - $nKSJ - 10;
  $nEPAKTE = (( 11 * $nGZ + 20 + $nKORR - $nKSJ ) % 30 );
  if (( $nEPAKTE == 25 OR $nGZ == 11 ) AND $nEPAKTE == 24 ) {
   $nEPAKTE = $nEPAKTE + 1;
  }
  $nN = 44 - $nEPAKTE;
  if( $nN < 21 ) {
   $nN = $nN + 30;
  }
  $nN = $nN + 7 - (( $nSO + $nN ) % 7 );
  $nN = $nN + isLeapYear( $nYEAR );
  $nN = $nN + 59;
  $nA = isLeapYear( $nYEAR );
  // Month
  $nNM = $nN;
  if ( $nNM > ( 59 + $nA )) {
   $nNM = $nNM + 2 - $nA;
  }
  $nNM = $nNM + 91;
  $nMONTH = div( 20 * $nNM, 611 ) - 2;
  // Day
  $nNT = $nN;
  $nNT = $nN;
  if ( $nNT > ( 59 + $nA )) {
   $nNT = $nNT + 2 - $nA;
  }
  $nNT = $nNT + 91;
  $nM = div( 20 * $nNT, 611 );
  $nDAY = $nNT - div( 611 * $nM, 20 );
  $dtEasterSunday = mktime( 0,0,0,$nMONTH,$nDAY,$nYEAR );
 }
 return $dtEasterSunday;
}
&#63;>

I hope this article will be helpful to everyone’s PHP programming design.

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