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PHP query operation to implement voting function, PHP query voting function_PHP tutorial

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2016-07-12 08:52:33805browse

php query operation to implement voting function, php query voting function

The example in this article shares the code of php query operation to implement voting function for your reference, the specific content is as follows

Title:

Summary of problem-solving methods:

Method 1:
1. Main voting page: 

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>投票</title>
<style>
#list
{
  width:400px;
  height:300px;}
#jieguo
{
  width:400px;
  height:300px;}
.x
{
   
  float:left;}
 
</style>
</head>
 
<body>
 
<form action="TouChuLi.php" method="post">
<&#63;php
include ("DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
$tmdh=$arr[0][0];
echo "<div><h2>{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$arrxx=$db->query($sqlxx);
echo "<div id='list'>";
foreach ($arrxx as $v)
{
  echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";
}
 
&#63;>
<input type="submit" value="提交">
<input type="button" value="查看结果" id="check" onclick="Showjieguo()">
</form>
</div>
 
<div id="jieguo" style="display:none">
<&#63;php
//计算总人数：
$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$zrs=$db->query($sqlzs);
 
foreach ($arrxx as $v)
{
   
  $name=$v[1];
  $number=$v[2];
  if($zrs[0][0]==0)
   {
     $bfb = 0;
   }
   else
   {
     $bfb = ($number/$zrs[0][0])*100;
   }
  $bfb=round($bfb,2);
  echo "<div>
    <span class='x'>{$name} </span>
    <div class='x' style='width:200px; height:10px; background-color:#808080'>
    <div style='width:{$bfb}%; height:10px; background-color:#FF8040'> </div>
    </div>
    <span class='x'>{$number} </span>
    <span class='x'>{$bfb}% </span>
    </div>
    <br />
    "; 
}
&#63;>
<input type="button" value="返回" id="fanhui" onclick="Showfanhui()">
</div>
<script>
function Showjieguo()
{
  document.getElementById("list").style.display="none";
  document.getElementById("jieguo").style.display="block";
  }
function Showfanhui()
{
  document.getElementById("list").style.display="block";
  document.getElementById("jieguo").style.display="none";
  }
</script>
 
</body>
</html>

2. Process the voting page: 

<&#63;php
$arr=$_POST["xx"];
include ("../DBDA.class.php");
$db=new DBDA();
 
 
foreach($arr as $v)
{
  $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";
  $db->Query($sql,1);//1代表$sql的类型
}
header ("location:TouPiao.php");
&#63;>

3. Create a class for accessing the database and encapsulate it for reference: 

<&#63;php
//执行一个sql语句，返回相应的结果
class DBDA
{
  public $host="localhost";//数据库服务器地址
  public $uid="root";//数据库用户名
  public $password="";//数据库密码
  //执行SQL语句的方法
  //参数里面：$sql代表要执行的sql语句；$type是sql语句的类型，0代表查询，1代表其他(增删改)；$db代表要操作的数据库
  function Query($sql,$type=0,$db="mydb")
  {
    //造连接对象
    $dbconnect=new MySQLi($this->host,$this->uid,$this->password,$db);
    //判断连接是否出错
    !mysqli_connect_error() or die("连接失败！");
    //执行sql语句
    $result=$dbconnect->query($sql);
    //判断SQL语句类型
    if($type==0)
    {
       //如果是查询语句返回结果集的二维数组
      return $result->fetch_all();
      }
    else
    {
      //如果是其他语句，返回true或false
      return $result;
      }   
    }
     
  }

Method 2:

1. Main voting page: 

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>投票</title>
<style>
.x
{
   
  float:left;}
 
</style>
</head>
 
<body>
 
<form action="TouChuLi.php" method="post">
<&#63;php
include ("../DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
$tmdh=$arr[0][0];
echo "<div><h2>{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$arrxx=$db->query($sqlxx);
echo "<div id='list'>";
foreach ($arrxx as $v)
{
  echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";
}
 
&#63;>
<input type="submit" value="提交">
<a href="ChaKan.php"><input type="button" value="查看结果" id="check" ></a>
</form>
</body>
</html>

2. Process voting page: 

<&#63;php
$arr=$_POST["xx"];
include ("../DBDA.class.php");
$db=new DBDA();
 
 
foreach($arr as $v)
{
  $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";
  $db->Query($sql,1);//1代表$sql的类型
}
header ("location:TouPiao.php");
&#63;>

3. View the voting results page: 

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>查看结果</title>
<style>
.x
{
  float:left;}
</style>
</head>
<body>
 
<&#63;php
include ("../DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
echo "<div><h2>{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'";
$arrxx=$db->query($sqlxx);
 
//计算总人数：
$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'";
$zrs=$db->query($sqlzs);
 
foreach ($arrxx as $v)
{
   $name=$v[1];//调研项目名称
   $number=$v[2];//选择该项的人数
   //判断总人数是否为0
   if($zrs[0][0]==0)
   {
     $bfb = 0;
   }
   else
   {
     $bfb = ($number/$zrs[0][0])*100;//求百分比
   }
   
  $bfb=round($bfb,2); //取小数点后两位
  echo "<div>
  <span class='x'>{$name} </span>
  <div class='x' style='width:200px; height:10px; background-color:#808080'>
  <div style='width:{$bfb}%; height:10px; background-color:#FF8040'> </div>
  </div>
  <span class='x'>{$number} </span>
  <span class='x'>{$bfb}%</span><br />
  </div><br />"; 
}
&#63;>
<br />
<a href="TouPiao.php"><input type="button" value="返回"></a>
</body>
</html>

Display results:

The above is the entire content of this article. I hope it will be helpful to everyone in learning PHP programming.

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