A dumb question, please give me some advice! ! !

<code>        function strToLeft($num,$arr){
            $i = $arr[$num];
            unset($arr[$num]);
            array_push($arr,$i);
            return $arr;
        }

        function combine_increase($arr, $start, $result, $count, $NUM, $arr_len,$newarr=array())  
        {  
          $i = 0;
          for ($i = $start; $i < $arr_len + 1 - $count; $i++)  
          {  
            $result[$count - 1] = $i;  
            if ($count - 1 == 0)  
            {  
              $tmp=array();
              for ($j = $NUM - 1; $j >= 0; $j--)  {
                array_push($tmp, $arr[$result[$j]]);
              }

              array_push($newarr, strToLeft(rand(0,$NUM-1),$tmp));
            }  
            else  {
              return combine_increase($arr, $i + 1, $result, $count - 1, $NUM, $arr_len); }
            
          }  
          return $newarr;
        } 
           $arr = array('a1','b2','c3','d4','e5','x1','y1','z1');
           $num = 3;  
           $result[$num]=array();
           $newarr=array();
           echo "('a1','b2','c3','d4','e5','x1','y1','z1')";//,'e5','x1'
           echo "<br/>";
           //combine_increase($arr, 0, $result, $num, $num, count($arr));
           echo "<pre class="brush:php;toolbar:false">";
           var_dump(combine_increase($arr, 0, $result, $num, $num, count($arr)));
           echo "

"; echo "
";

This is a one-dimensional data generated by n one-dimensional arrays with different combinations of three elements. Normally, if it is not returned, just array_push($newarr, strToLeft(rand(0,$NUM-1),$tmp) ); the sentence becomes

<code>          var_dump(strToLeft(rand(0,$NUM-1),$tmp));
          echo("<br/>");  
          
          则能列出几十条结果，但通过返回数组就只返回6个，好像是前6个，不知道如何能全部返回取到，求解！！！！</code>

Reply content:

<code>        function strToLeft($num,$arr){
            $i = $arr[$num];
            unset($arr[$num]);
            array_push($arr,$i);
            return $arr;
        }

        function combine_increase($arr, $start, $result, $count, $NUM, $arr_len,$newarr=array())  
        {  
          $i = 0;
          for ($i = $start; $i < $arr_len + 1 - $count; $i++)  
          {  
            $result[$count - 1] = $i;  
            if ($count - 1 == 0)  
            {  
              $tmp=array();
              for ($j = $NUM - 1; $j >= 0; $j--)  {
                array_push($tmp, $arr[$result[$j]]);
              }

              array_push($newarr, strToLeft(rand(0,$NUM-1),$tmp));
            }  
            else  {
              return combine_increase($arr, $i + 1, $result, $count - 1, $NUM, $arr_len); }
            
          }  
          return $newarr;
        } 
           $arr = array('a1','b2','c3','d4','e5','x1','y1','z1');
           $num = 3;  
           $result[$num]=array();
           $newarr=array();
           echo "('a1','b2','c3','d4','e5','x1','y1','z1')";//,'e5','x1'
           echo "<br/>";
           //combine_increase($arr, 0, $result, $num, $num, count($arr));
           echo "<pre class="brush:php;toolbar:false">";
           var_dump(combine_increase($arr, 0, $result, $num, $num, count($arr)));
           echo "

"; echo "
";

This is a one-dimensional data generated by n one-dimensional arrays with different combinations of three elements. Normally, if it is not returned, just array_push($newarr, strToLeft(rand(0,$NUM-1),$tmp) ); the sentence becomes

<code>          var_dump(strToLeft(rand(0,$NUM-1),$tmp));
          echo("<br/>");  
          
          则能列出几十条结果，但通过返回数组就只返回6个，好像是前6个，不知道如何能全部返回取到，求解！！！！</code>

I don’t understand your question. You can’t find return in combine_increase, so why should return be null?

I understand the problem, but I don’t understand the code. There are too many parameters in a mess

If you just implement an array that returns different values, there is no need to go to such trouble

And the direct output strToLeft(rand(0,$NUM-1),$tmp) results in six