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html - how to terminate php code
- WBOYOriginal
- 2016-07-06 13:51:281321browse
What I wrote is a subpage that receives form data. This subpage receives a data and automatically generates two corresponding files in the directory based on the received data. Now I want to add a judgment that if the file exists, it will not be executed to generate two files. If the code of a file does not exist, execute the code to generate the file (now only output whether the link exists) my code looks like this
<code><html>
<head>
<title>XXX</title>
</head>
<body>
<?php
$filename = @$_POST['数据1']."/index.htm";
if(!file_exists($filename)){mkdir(@$_POST['数据1']);}
file_put_contents($filename,'文件内容1
'); ?>
<?php
$file = @$_POST['数据1']."/233.htm";
file_put_contents($file,'文件内容2
'); ?>
<?php
$dir = @$_POST['数据1'];
$file = @$_POST['数据1']."/index.htm";
if(file_exists($file))
{
echo "链接已存在 www.XXX.com/".$dir."";
}
else
{
echo "您的链接是".$dir."";
}
; ?>
</body>
</html>
</code>
Baidu found an exit function that looks like this
<code><?php
$site = "http://www.w3school.com.cn/";
fopen($site,"r")
or exit("Unable to connect to $site");
?>
</code>
But if you add <?php ?> directly, it will become php nested within php, and you will be stuck in a puzzle
If the answer you gave me is exit or die, I will write it like this
<code><html>
<head>
<title>XXX</title>
</head>
<body>
<?php
$dir = @$_POST['数据1'];
$file = @$_POST['数据1']."/index.htm";
if(file_exists($file))
{
echo "链接已存在 www.XXX.com/".$dir."";
}
else
{
echo "您的链接是".$dir."";
exit("
<?php
$filename = @$_POST['数据1']."/index.htm";
if(!file_exists($filename)){mkdir(@$_POST['数据1']);}
file_put_contents($filename,'文件内容1
'); ?>
<?php
$file = @$_POST['数据1']."/233.htm";
file_put_contents($file,'文件内容2
'); ?>
")
}; ?>
</body>
</html>
这样的话变成php套嵌php 会报错的</code>
Reply content:
What I wrote is a subpage that receives form data. This subpage receives a data and automatically generates two corresponding files in the directory based on the received data. Now I want to add a judgment that if the file exists, it will not be executed to generate two files. If the code of a file does not exist, execute the code to generate the file (now only output whether the link exists) my code looks like this
<code><html>
<head>
<title>XXX</title>
</head>
<body>
<?php
$filename = @$_POST['数据1']."/index.htm";
if(!file_exists($filename)){mkdir(@$_POST['数据1']);}
file_put_contents($filename,'文件内容1
'); ?>
<?php
$file = @$_POST['数据1']."/233.htm";
file_put_contents($file,'文件内容2
'); ?>
<?php
$dir = @$_POST['数据1'];
$file = @$_POST['数据1']."/index.htm";
if(file_exists($file))
{
echo "链接已存在 www.XXX.com/".$dir."";
}
else
{
echo "您的链接是".$dir."";
}
; ?>
</body>
</html>
</code>
Baidu found an exit function that looks like this
<code><?php
$site = "http://www.w3school.com.cn/";
fopen($site,"r")
or exit("Unable to connect to $site");
?>
</code>
But if you add <?php ?> directly, it will become php nested within php, and you will be stuck in a puzzle
If the answer you gave me is exit or die, I will write it like this
<code><html>
<head>
<title>XXX</title>
</head>
<body>
<?php
$dir = @$_POST['数据1'];
$file = @$_POST['数据1']."/index.htm";
if(file_exists($file))
{
echo "链接已存在 www.XXX.com/".$dir."";
}
else
{
echo "您的链接是".$dir."";
exit("
<?php
$filename = @$_POST['数据1']."/index.htm";
if(!file_exists($filename)){mkdir(@$_POST['数据1']);}
file_put_contents($filename,'文件内容1
'); ?>
<?php
$file = @$_POST['数据1']."/233.htm";
file_put_contents($file,'文件内容2
'); ?>
")
}; ?>
</body>
</html>
这样的话变成php套嵌php 会报错的</code>
Wouldn’t it be better to just do this...
<code class="php"><?php
$dir = @$_POST['数据1'];
$filename = $dir . "/index.htm";
if (file_exists($filename)) {
echo "链接已存在 www.XXX.com/" . $dir . "\n";
exit("链接已存在");
} else {
mkdir($dir);
}
file_put_contents($filename, '文件内容1 ');
//另外一个文件一样做
//$file = $dir . "/233.htm";
//file_put_contents($file, '文件内容2 ');
</code>
update:
<code class="php"><html>
<head>
<title>XXX</title>
</head>
<body>
<?php
$dir = @$_POST['数据1'];
//$dir = 'test223';
$filename = $dir . "/index.htm";
if (file_exists($filename)) {
echo "链接已存在 www.XXX.com/:2333" . $dir . "\n";
exit("链接已存在");
} else {
if (!file_exists($dir)) {
mkdir($dir);
echo "您的链接是" . $dir . "";
}
}
file_put_contents($filename, '
文件内容1
');
$file = $dir . "/233.htm";
file_put_contents($file, '
文件内容2
');
?>
</body>
</html></code>
<code><html>
<head>
<title>XXX</title>
</head>
<body>
<?php
$dir = @$_POST['数据1'];
$filename = @$_POST['数据1']."/index.htm";
if(file_exists($filename ))
{
echo "链接已存在 www.XXX.com/".$dir."";
exit();
}
else
{
echo "您的链接是".$dir."";
mkdir(@$_POST['数据1']);;
};
file_put_contents($filename,'文件内容1');
$file = @$_POST['数据1']."/233.htm";
file_put_contents($file,'文件内容2');
?>
</body>
</html></code>
Change it to this
If it is already within the <?php tag, there is no need to write it again. .