The default value of a two-dimensional array is empty. How to determine if it is empty and not execute the code inside the if?

<code>$pet = array(["name"]=>array('','','')["age"]=>array('','',''));

if($pet){
    echo $pet
}

具体代码如上，当数组有值时，才输出。 本人用if 判断失败。</code>

Reply content:

<code>$pet = array(["name"]=>array('','','')["age"]=>array('','',''));

if($pet){
    echo $pet
}

具体代码如上，当数组有值时，才输出。 本人用if 判断失败。</code>

<code>$pet = array("name"=>array('','',''),"age"=>array('','',''));

foreach($pet as $pKey => $pVal){

    $pet[$pKey] = array_filter($pVal);
}
$pet = array_filter($pet);

if(!empty($pet)){
    var_dump($pet);
}
</code>

Is this the main point of the question?

1, code error,

<code>name和age是二维数组的key，之间要逗号隔开。

$pet = array(["name"]=>array('','',''),["age"]=>array('','',''));

if($pet){
    echo $pet
}
</code>

2. When you say "the array is output only when it has a value", does it mean $pet, or name or age.

<code>array_filter过滤一下空数组。
</code>