It's a very simple problem, please help me solve it, thank you. _html/css

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It's a very simple problem, please help me solve it, thank you. _html/css_WEB-ITnose

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Jun 24, 2016 pm 12:15 PM

I want to use CSS to set the background of a button:
That is, the background is picture 1.png when not clicked, and the background picture is 2.png after clicking (that is: when selected).
Is there any good solution? Thank you.
I found a solution online like this:
<script> <br /> var Arr=new Array( "1.jpg ", "2.jpg ") <br /> var i=0 <br /> function fun(){ <br /> aa.style.backgroundImage= "url( " Arr[i] ") " <br /> i=i 1 <br /> if(i> =2)i=0 <br /> } <br /> </script>

aaaa

Reply to discussion (solution)

Use div instead of button

Demonstration effect: http://job.dingso.com/crm/mail.php I wrote a button Style

Yes, use DIV, and this does not require JS to control at all, it can be written directly with CSS www.seo7ye.com

Yes, use DIV, and this does not require JS to control at all, it can be written directly with CSS www.seo7ye.com
Please give me some advice:
How to control without JS? Write?

I don’t need to teach you how to define two classes bg1 bg2

First of all, point out a few mistakes. There are many unnecessary spaces in the original poster’s code, such as id="aa " , i> =2, etc. This is a reason why the program cannot run. In addition, aa.style.backgroundImage, aa is not defined, and there are no other big problems. I have posted the detailed code below and put it in the same folder. Just two pictures can be run

<!DOCTYPE html><html><head><script>  var Arr=new Array( "1.jpg", "2.jpg")  var i=0 ;function fun(){   var aa=document.getElementById("aa");   aa.style.background="url("+Arr[i]+ ")";   i=i+1;    if(i>=2)     i=0;}</script>  </head><body><table width=500 height=100 id= "aa" background="1.jpg" >  <tr> <td>  aaaa  </td> </tr>  </table>  <input type="submit" value="Button" id="bb" onClick="fun();"/></body></html>

How to define two classes bg1 bg2 You don’t need me to teach you

Thank you, yes, this method compares good.

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